Answer:
The given grammar is :
S = T V ;
V = C X
X = , V | ε
T = float | double
C = z | w
1.
Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.
From the given grammar,
Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.
No other variables generate variable X or ε.
So, only variable X is nullable.
2.
First of nullable variable X is First (X ) = , and ε (epsilon).
L.H.S.
The first of other varibles are :
First (S) = {float, double }
First (T) = {float, double }
First (V) = {z, w}
First (C) = {z, w}
R.H.S.
First (T V ; ) = {float, double }
First ( C X ) = {z, w}
First (, V) = ,
First ( ε ) = ε
First (float) = float
First (double) = double
First (z) = z
First (w) = w
Explanation:
Answer:
Given Data:
concentration of sewer Csewer = 1.2 g/L
converting into mg/L = Csewer = 1.2 g/L x 1000 mg/g = 1200 mg/L
flow rate of sewer Qsewer = 2000 L/min
concentration of sewer Cstream = 20 mg/L
flow rate of sewer Qstream = 2m3/s
converting Q into L/min = 2m3/s x 1000 x 60 = 120000 L/min
mass diagram is
Answer:
Energy produce in one year =20.49 x 10¹⁶ J/year
Explanation:
Given that
Plant produce 6.50 × 10⁸ J/s of energy.
It produce 6.50 × 10⁸ J in 1 s.
We know that
1 year = 365 days
1 days = 24 hr
1 hr = 3600 s
1 year = 365 x 24 x 3600 s
1 year = 31536000 s
So energy produce in 1 year = 31536000 x 6.50 × 10⁸ J/year
Energy produce in one year = 204984 x 10¹² J/year
Energy produce in one year =20.49 x 10¹⁶ J/year
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