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3 years ago

A tension member must be designed for a service dead load of 18 kips and a service live load of 2 kips.

Engineering

1 answer:

ella [17]3 years ago

4 0

Answer:

A) max factored load ( pv = 1.4 * 18 ) = 25.2 kips

B) max load factored load = ( Pa = 18 + 2 ) = 20 kips

Explanation:

service dead load = 18 kips

service live load = 2 kips

A) Determine the maximum factored load and controlling AISC load combination

max factored load ( pv = 1.4 * 18 ) = 25.2 kips

DL = 18 kips

LL = 2 kips

B) Determine the max load and controlling AISC load combination

max load factored load = ( Pa = 18 + 2 ) = 20 kips

attached below

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sashaice [31]

Answer:

The horizontal lines of the orthographic drawing

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4 years ago

A fluidis flowing through a capillary

Illusion [34]

Answer:

The velocity of the fluid is 1.1012 m/s

Solution:

As per the question, for the fluid:

Diameter of the capillary tube, d = 1.0 mm = $1.0\times 10^{- 3} m$

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Now, for the fluid velocity, we use the relation:

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3 years ago

The importance of reading a circuit diagram to interpret a wiring diagram?

Nataly [62]

Answer:

The ability to read electrical schematics is a really useful skill to have. To start developing your schematic reading abilities, it's important to memorize the most common schematic symbols. ... You should also be able to get a rough idea of how the circuit works, just by looking at the schematic.

Explanation:

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3 years ago

The inverted U-tube is used to measure the pressure difference between two points A and B in an inclined pipeline through which

JulijaS [17]

Answer:

i) 0.610 m or 610 mm

ii) 0.4 m or 400 mm

Explanation:

The pressure difference between the pipes is

a) Air

Pa + πha +Ha = Pb + πhb +Hb

Pa - Pb = π(hb-ha) + Hb-Ha

Relative density of air = 1.2754 kg /m3

Pa - Pb = 1.2754 * 0.4 + (0.3-0.2) = 0.610 m or 610 mm

b) paraffin of relative density of 0.75

Pa - Pb = π(hb-ha) + Hb-Ha

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3 years ago

Consider a 8-m-long, 8-m-wide, and 2-m-high aboveground swimming pool that is filled with water to the rim. (a) Determine the hy

Stolb23 [73]

Answer:

The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.

Explanation:

To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is $\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)$

$\equiv \rho g h^{2} l$ , we know ρ=density of fluid=1000 $g / c m^{3}$ ,

g=acceleration due to gravity=9.81 $m / s^{2}$ , h=height of the pool=2 m and l=length of the pool=8 m.

hydrostatic force on each wall= $1000 \times 9.81 \times 2^{2} \times 8$ = 313920 N.

The distance at which hydrostatic force is acted is half of the height of the swimming pool.

At 1 m from the ground this hydrostatic force is acted on each wall.

The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation = $\rho g h^{2} l$ = $1000 \times 9.81 \times 4^{2} \times 8$ = 1255680 N. This is 4 times 313920 N.

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3 years ago