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tresset_1 [31]
3 years ago
12

Passes through (1.2) and (3, -8). with y=mx+b

Mathematics
2 answers:
notka56 [123]3 years ago
7 0

Answer:

y = -5x - 10

Step-by-step explanation:

-8-2          -10

____    =   ___   =     -5

3 - 1           2

mr Goodwill [35]3 years ago
3 0

Answer:

  • y = -5x + 7

Step-by-step explanation:

<u>Find the slope:</u>

  • m = (- 8 - 2) / (3 - 1) = -10 / 2 = -5

<u>Use the point (1, 2) and find the equation:</u>

  • y - 2 = -5(x - 1)
  • y = -5x + 5 + 2
  • y = -5x + 7
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The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original
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<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

{:\implies \quad \sf 5(s+8)=65}

{:\implies \quad \sf 5s+5\times 8=65}

{:\implies \quad \sf 5s+40=65}

{:\implies \quad \sf 5s=65-40}

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{:\implies \quad \sf s=\dfrac{25}{5}=5}

{:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}

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<em>Hence, the original side's length 5 inches </em>

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The sum of two numbers is 47 and the difference is 25 . what are the numbers?
taurus [48]
The numbers are:  36 and 11 .
______________________________________________
Explanation:
______________________________________________
Let us represent the TWO (2) numbers with the variables;
         "x" and "y" .
__________________________________________
     x + y = 47 .

     y − x = 25.
__________________________________________
Since:  " y − x = 25 " ;

Solve for "y" in terms of "x" ;

  y − x = 25  ;

Add "x" to each side of the equation:
_____________________________________________
   y − x + x  = 25 + x  ;

to get:

   y = 25 + x .

Now, since:

  x + y = 47 ;

Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :

x + (25 + x) = 47  ;

x + 25 + x + 47 ;

2x + 25 = 47 ;

Subtract "25" from each side of the equation:

2x + 25 − 25 = 47 − 25 ;

2x  = 22  ;

Divide EACH SIDE of the equation by "2" ;
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    x = 11 ;
______________________________________________
x + y = 47<span> ;

</span>Plug in "11" for "x" into the equation ; to solve for "y" ;

11 + y = 47 ;

Subtract "11" from EACH SIDE of the equation;
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 11 + y − 11 =  47 − 11  ;

            y = 36 .
___________________________________________
So:  x = 11 , y = 36 ;
___________________________________________
 Let us check our work:

y − x = 25 ;

36 − 11 =? 25 ?  Yes!

x + y = 47 ;

36 + 11 =? 47 ? Yes!
______________________________________________
The numbers are:  36 and 11 .
______________________________________________
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3 years ago
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