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3 years ago

Plz help

Physics

1 answer:

Darya [45]3 years ago

8 0

Answer:

Stored energy

Explanation:

For example, if you have a ball sitting on top of a hill it has potential energy. The ball has the potential to start rolling, but it hasn't yet. So you could say that the ball is storing this potential energy until it gets converted to another form. (Such as kinetic energy)

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A positive charge Q is distributed uniformly along the positive y-axis between y=0 and y=a. A negative point charge, -q, lies on

mihalych1998 [28]

This can be done using integration and vector analysis. By considering a differential element of the line charge distribution dq = Q/a*dy, we could calculate the dFx and dFy and solve for Fx and Fy through integration.

dFx = -xkQdq / (y^2 + x^2)^3/2 = -xkQ^2/a/(y^2+x^2)^(3/2)*dy
Fx = integral from 0 to a -xkQ^2/a/(y^2+x^2)^(3/2)*dy
Fx = -xkQ^2/a*int(0, a, dy/(y^2+x^2)^(3/2))
Fx = -kQ^2/x(a^2+x^2)^(1/2)

dFy = kQy/(y^2+x^2)^(3/2) * dq
dFy = kQ^2/a*y/(y^2+x^2)^(3/2)*dy
Fy = int(0, a, kQ^2/a*y/(y^2+x^2)^(3/2)*dy)
Fy = kQ^2/a int(0, a, dy y/(y^2+x^2)^(3/2))
Fy = kQ^2/a * (1/x - 1/(a^2+x^2)^(1/2))

5 0

3 years ago

a cup of coffee has a mass of .297 kg if you place this cup of coffee on a desk and let it sit there undisturbed how much force

Dominik [7]

The force of the table upon the cup is 2.9106 N

4 0

2 years ago

a toy car is wound up and released on the floor. it accelerates at a rate of 0.4 m/s/s . the mass of the care is 3kg. what is th

EastWind [94]

Answer:

1.2N

Explanation:

f=m×a

m=3kg

a=.4m/s/s

3×.4=1.2

kg×m/s/s = N

8 0

3 years ago

Determine the centroid of the shaded area shown in figure 2. Determine the moment of inertia about y-axis of the shaded area sho

Nady [450]

Answer:

centroid: (x, y) = (81.25 mm, 137.5 mm)
I = 8719.31 mm^2 for unit mass

Explanation:

Finding the desired measures requires we know a differential of area. That, in turn, requires we have a way to describe a differential of area. Here, we choose to use a vertical slice, which requires we know the area boundaries as a function of x.

The upper boundary is a line with a slope of 125/156.25 = 0.8, and a y-intercept of 125. That is, ...

y1 = 0.8x +125

The lower boundary is given in terms of y, but we can solve for y to find ...

100x = y^2

y2 = 10√x

Then our differential of area is ...

dA = (y1 -y2)dx

The centroid is found by computing the first moment about the x- and y-axes, and dividing those values by the area of the figure.

The area will be ...

$\displaystyle A=\int_0^{156.25}{dA}=\int_0^{156.25}{(y_1-y_2)}\,dx$

The y-coordinate of the centroid is ...

$\displaystyle \overline{y}=\dfrac{S_x}{A}=\dfrac{1}{A}\int_0^{156.25}{\dfrac{y_1+y_2}{2}}\,dA=\dfrac{1}{A}\int_0^{156.25}{\dfrac{y_1+y_2}{2}(y_1-y_2)}\,dx=137.5$

Similarly, the x-coordinate is ...

$\displaystyle \overline{x}=\dfrac{S_y}{A}=\dfrac{1}{A}\int_0^{156.25}{x}\,dA=\dfrac{1}{A}\int_0^{156.25}{x(y_1-y_2)}\,dx=81.25$

That is, centroid coordinates are (x, y) = (81.25, 137.5) mm.

The moment of inertia is the second moment of the area. If we normalize by the "mass" (area), then the integral looks a lot like the one for $\overline{x}$ , but multiplies dA by x^2 instead of x.

The attachment shows that value to be ...

I ≈ 8719.31 mm^2 (normalized by area)

The area is 16276.0416667 mm^2, if you want to "un-normalize" the moment of inertia.

7 0

3 years ago

An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s, what is he acceleration down the

krok68 [10]

Given :

An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s.

To Find :

The acceleration down the hill.

The force needed for that kind of acceleration.

Solution :

By equation of motion :

$v^2 -u^2 = 2as\\\\a = \dfrac{v^2-u^2}{2s}\\\\a = \dfrac{15^2 -0^2}{2\times 100}\\\\a = 1.125\ m/s^2$

Force required is, F = ma

F = 80×1.125 N

F = 90 N

Hence, this is the required solution.

6 0

3 years ago