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A falling raindrop
Kinetic energy and potential energy are both applied when a body or object is falling.
Answer:
a) x = 660 m
, b) λ = 0.330 m
, c) precision is 0.1 cm
, d) Δf= n Δt/ t²
Explanation:
a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is
v = x / t
x = v t
x = 330 2
x = 660 m
b) the speed of sound is
v = λ f
λ = v / f
λ = 330/1000
λ = 0.330 m
c) a measuring tape must be used to measure the wavelength, the precision is 0.1 cm
.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency
.f = n / t
Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s
Δf / f = Δt / t
Δf = Δt /t f
Δf= n Δt/ t²
Answer:
4
Explanation:
We know that intensity I = P/A where P = power and A = area through which the power passes through.
Now, let the initial intensity of the speaker be I₀ and its initial power be P₀. Since the intensity is increased by a factor of 4, the new intensity be I and new power be P.
So, I = P/A and I₀ = P₀/A
Now, if I = 4I₀,
P/A = 4P₀/A
P = 4P₀
Now, energy E = Pt, where t = time. So, P = E/t and P₀ = E₀/t
Substituting P and P₀ into the equation, we have
P = 4P₀
E/t = 4E₀/t
E = 4E₀
Since the energy is four times the initial energy, the energy output increases by a factor of 4.