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ra1l [238]
3 years ago
7

Problem (2): Two point charged particles are 4.41cm apart. They are moved and placed in a new position. The force between them i

s found to have been tripled. How far apart are they now?​
Physics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

HI

Explanation:

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Yanka [14]
Make sure to thank me

The answers are by:

Investigation
Sampling
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4 years ago
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A lamp uses a 230 V mains supply and transfers 96 J of energy every second. Work out the current through the lamp. Give your ans
sertanlavr [38]

Answer:

0.4 A

Explanation:

From the question,

Electric power = Voltage×current

P = VI.......................... Equation 1

Make I the subject of the equation

I = P/V..................... Equation 2

Given: P = 96 J/s, V = 230 V.

Substitute into equation 2

I = 96/230

I = 0.4 A.

Hence the current is 0.4 A

8 0
4 years ago
A very small tilt in Earth’s axis would likely cause ____.
olchik [2.2K]
If the Earth's axis were closer to "straight up and down" than
the present 23.5°, then . . .

-- The areas around the north and south poles where the sun
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directly overhead, would be narrower.

-- There would be less difference, everywhere, between the
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An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

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p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: f=-f

and we also know that the object is placed a distance of twice the focal length, so p=2f

So we can find q from the equation above

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

And the magnification of the image is given by

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

5 0
4 years ago
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Which numbers on the ph scale indicate an acid
KiRa [710]

Answer:

0 - 6.9 --> Acidic

Explanation:

4 0
3 years ago
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