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3 years ago

Most of the elements (85%) in the periodic table are.

Physics

2 answers:

RideAnS [48]3 years ago

8 0

Answer:

Metals

Explanation:

Rasek [7]3 years ago

4 0

Most of the elements are metals

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What test were used to find out information about the iceman

Blababa [14]

To find information, the would take DNA tests.

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3 years ago

A device that uses the wet/dry bulb method to measure the ___________________is the sling psychrometer. As seen here, two thermo

makvit [3.9K]

I would say the answer is D

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hygrometer is a weather instrument used to measure the amount of humidity in the atmosphere. There are two main types of hygrometers -- a dry and wet bulb psychrometer and a mechanical hygrometer.

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3 years ago

How much time would it take for the sound of thunder to travel 1,500 meters if sound travels at a speed of 330 m/sec?

Fittoniya [83]

(1,500 meters) x (1 sec / 330 meters) = (4 and 18/33) seconds

(4.55 sec, rounded)

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3 years ago

Read 2 more answers

How do I find the speed of sound when given Frequency and displacement?

IceJOKER [234]

Answer: Taking into account sound is a wave, we can use the information of the displacement (generally given as a graph) to find the wavelength and frequency, then we can calculate the speed with the formula of the speed of a wave.

Explanation:

If we have the displacement graph of the sound wave, we can find its amplitude, its wavelength and period (which is the inverse of frequency).

Now, if we additionally have the frequency as data, we can use the equation of the speed of a wave:

$s=\lambda f$

Where:

$s$ is the speed of the sound wave

$\lambda$ is the wavelength

$f$ is the frequency

3 0

3 years ago

Suppose electric power is supplied from two independent sources which work with probabilities 0.4, 0.5, respectively. if both so

sattari [20]

Answer:

The answers to the questions are as follows

a) k = 0, P = 0.3

k = 1, P = 0.5

k = 0, P = 0.2

b) The probability that enough power will be available is 0.5.

Explanation:

To solve the question we write the parameters as follows

Probability that the first power source works = P(A) = 0.4

Probability that the second power source works = P(B) = 0.5

When both sources are supplying power we have the probability = 1

If non of them is producing the probability = 0

a) The probability that exactly k sources work for k=0,1,2 is given by

For k = 0, probability = (1- P(A))× (1- P(B)) = 0.6 × 0.5 =0.3

Therefore the probabilities that exactly 0 source work = 0.3

for k = 1 we have the probability = P(A)(1-P(B)) + P(B)(1-P(A)

= 0.4(1-0.5)+0.5(1-0.4) = 0.2 + 0.3 = 0.5

The probabilities that exactly 1 source work = 0.5

for k = 2 we have the probability given by = P(A) × P(B) = 0.4 × 0.5 = 0.2

Therefore the probability that exactly 2 sources work = 0.2

b) The probability that enough power will be available is

0 × P(k = 0) + 0.6 × P(k = 1) + 1 × P(k = 2)

0 × 0.2 + 0.6 × 0.5 + 1 × 0.2 = 0.5

The probability that enough power will be available is 0.5.

3 0

3 years ago