Answer:
MgSO4.7H2O
Explanation:
Let the formula for the hydrated magnesium sulphate be MgSO4.xH2O
Mass of the hydrated salt (MgSO4.xH2O) = 12.845g
Mass of anhydrous salt (MgSO4) = 6.273g
Mass of water molecule(xH2O) = Mass of the hydrated salt — Mass of anhydrous salt = 12.845 — 6.273 = 6.572g
Now,we can obtain the number of mole of water molecule present in the hydrated salt as follows:
Molar Mass of hydrated salt (MgSO4.xH2O) = 24 + 32 + (16x4) + x(2 + 16) = 24 + 32 + 64 + x(18) = 120 + 18x
Mass of xH2O/ Molar Mass of MgSO4.xH2O = Mass of water / mass of hydrated salt
18x/120 + 18x = 6.572/12.845
Cross multiply to express in linear form
18x x 12.845 = 6.572(120 + 18x)
231.21x = 788.64 + 118.296x
Collect like terms
231.21x — 118.296x = 788.64
112.914x = 788.64
Divide both side by 112.914
x = 788.64 /112.914
x = 7
Therefore the formula for the hydrated salt (MgSO4.xH2O) is MgSO4.7H2O
Where are the following statements ??
Answer:
2
Explanation:
because on the product side you have 2 sulfurs so you need 2 on the reactant side.
Q, R, S, P is the order of apparent magnitude of the stars, starting from the least to the greatest.
Answer: Q, R, S, P
<u>Explanation:</u>
The apparent magnitudes of the star is the brightness calculated by an observer at a particular distance from the Earth. The smaller the distance between the star and the Earth, the greater the apparent brightness.
So , from the given distance (in light years), Q,R,S,P is the answer (least to the greatest apparent magnitude) (distance is greatest to least).
To find the molecular formula of the compound, we get the molar mass of empirical formula CH2o which is 30 g/mol. We divided the molecular mass of 90.087 g/mol by 30, we get 3. Hence, we multiply each element by 3, getting the molecular formula of C3H6O3.
