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saveliy_v [14]
3 years ago
5

A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work

Chemistry
1 answer:
DENIUS [597]3 years ago
7 0
Data:
V_{initial} = 590\:mL
T_{initial} = -55.0^0C
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → T_{initial} = 218.0\:K
V_{final} = ? (in\:milliliters)
T_{final} = 30.0^0C
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → T_{final} = 303.0\:K

By the first Law of Charles and Gay-Lussac, we have: 
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }

Solving:
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }
\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }
Product of extremes equals product of means:
218.0* V_{f} = 590*303.0
218.0 V_{f} = 178770
V_{f} = \frac{178770}{218.0}
\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark
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Yanka [14]

Answer:

See explanation

Explanation:

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8 0
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Which of the following atoms would have a charge of +1?
erica [24]

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3 years ago
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Radon (Rn) is the heaviest, and only radioactive, member of Group 8A(18) (noble gases). It is a product of the disintegration of
Serggg [28]

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no. of moles =1.0/226g/mol           =0.04424moles

no. of atoms in 0.044moles

no. of atoms =no. of moles x avogadro's number

= 0.044x 6.022 x10^23                  = 0.264968 x 10^22

 If 10^15  atoms of Ra produce 1,373*10^4  atoms of<u> Rn per second</u> then 2,66 *10^21  forms 3,658*10^10 atoms of Rn per second.

Day has 246060=86400 s

That means that 2,66x10^21  atoms of Ra produces 3,16 x10^15  atoms of Rn in a day.

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n(Rn)=5,25*10−9                              pV=nR*T

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V=5.25∗10^−9 ∗ 8.314 ∗ 273.15  /  101325

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To know more about Ra here

brainly.com/question/9112754

#SPJ4

6 0
2 years ago
Find the specific heat of an unknown material with an initial temperature of 20°C, when 5000 Joules are applied to a 50 gram sam
xxTIMURxx [149]

Answer:

2J/g°C

Explanation:

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c = 5000 / 2500

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The specific heat capacity of the substance is 2J/g°C

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