10,11,15 is not right triangle
30,40,50 is right triangle
9,13,16 is not right angel
16,30,34 is right triangle
What do you need help will I don't see an question or anything
Clearly, |S| = 50.
Count the multiples of 2 between 1 and 50:
⌊50/2⌋ = ⌊25⌋ = 25
(where ⌊x⌋ denotes the "floor of x", or the largest integer that is smaller than or equal to x; in other words, round <u>down</u> to the nearest integer)
Count the multiples of 3 between 1 and 50:
⌊50/3⌋ ≈ ⌊16.667⌋ = 16
Since LCM(2, 3) = 6, the sets of multiples of 2 and multiples of 3 have some overlap. Count the multiples of 6 between 1 and 50:
⌊50/6⌋ ≈ ⌊8.333⌋ = 8
Then by the inclusion/exclusion principle, we remove from S
25 + 16 - 8 = 33
elements, so that the new set S contains 50 - 33 = 17 elements.
Answer:
g(p)h(p) = = p^4 + 2p^3 - 8p^2 -2p + 4
Step-by-step explanation:
Hello!
We will use the distributive property:
g(p) h(p) = ( p - 2 ) * ( p^3 + 4p^2 - 2 ) = ( p^3 + 4p^2 - 2 ) * ( p - 2 )
The distributive property allow us to multiply the first term <em>(p^3 + 4p^2 - 2) </em>by every member of the second member, that is <em>p </em>and <em>-2.</em>
g(p) h(p) = ( p^3 + 4p^2 - 2 ) * p + ( p^3 + 4p^2 - 2 ) * (-2)
Now we can do the same for the two resulting terms, that is, we can multiply every term in parenthesis<em> ( p^3 + 4p^2 - 2 ) </em>by the term on the rigth:
( p^3 + 4p^2 - 2 ) * p = (p^3)*p + (4p^2)*p - 2*p = p^4 + 4p^3 -2p
( p^3 + 4p^2 - 2 ) * (-2) = (p^3)*(-2) + (4p^2)*(-2)- 2*(-2) = -2p^3 - 8p^2 + 4
And now we can sum both terms and add monomials with the same exponent of t. Look at the underlined terms
g(p) h(p) = p^4 + <em><u>4p^3</u></em><em> </em>-2p - <u>2p^3 </u>- 8p^2 + 4 = p^4 +<em><u>2p^3</u></em> -2p - 8p^2 + 4
= p^4 + 2p^3 - 8p^2 -2p + 4
Answer:
37
Step-by-step explanation:
38 + u actually thought lol
