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slamgirl [31]
2 years ago
6

How is nominal scale type related to diversity?

Biology
1 answer:
Anna71 [15]2 years ago
7 0

Answer: A

Explanation: :3

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Each of the four pedigrees that follow represents a human family within which a genetic disease is segregating. Affected individ
Ne4ueva [31]

 Answer:

<u> The following four traits are -: </u>

  • <u>Pedigree 1 -</u> A recessive trait (autosomal recessive)  is expressed by pedigree 1.
  • <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
  • <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
  • <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.    

Explanation:

<u>Explaination of each pedigree chart</u>-

  • Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected. X^A In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa)
  • <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical  Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (X^A) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical X^A must be contributed by II-6.
  • The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
  • <u>Pedigree 4</u> is an <u>X-linked dominant function</u> characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.    

In the question the pedigree chart was missing ,hence it is given below.

     

7 0
3 years ago
What is the colorless, odorless gas that binds to red blood cells causing the body not to get the oxygen it needs?
Juliette [100K]

Answer:

Therefore,when carbon monoxide is present,it blind to hemoglobin preferentially over oxygn.As a result,oxygen cannot blind to hemoglobin ,so very little oxygen is transported through the body carbon monoxide is a colorless odorless gas and is therefore difficult detect.

7 0
2 years ago
Why are dead or weakened viruses used instead of normal viruses to create a vaccine?
vodomira [7]
I think its because vaccines are just to help your body learn how to fight off the virus, it’s not to actually give you the virus. Hope this helped!
5 0
2 years ago
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How could you investigate the idea that DNA is found only in living or once-living things?
Phoenix [80]

Answer: Cloning, dude just watch jurassic park

Explanation:

4 0
3 years ago
Why do you think that there are earthquakes in mid-america where there are no fault lines
Dvinal [7]
Earthquakes only occur at transfer boundaries where two tectonic plates will slide or rub past each other.
If there are no boundaries in mid-America, then earthquakes are not possible.
5 0
3 years ago
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