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bezimeni [28]
3 years ago
8

How many lines are determined by two points?

Mathematics
1 answer:
Nataly [62]3 years ago
5 0
2 lmbo are you ok dude lol 
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-3 (C - 10) + -4 = 2<br> C =
DENIUS [597]
-3(c-10) + -4= 2
-3c+ 30+ -4= 2
-3c + 26= 2
-3c= -24
C= 8
7 0
3 years ago
Read 2 more answers
Carla is age 32. how many quarters of coverage does she need to be fully insured
never [62]
According to my research, And I would take this with a grain of salt since I am not a insurance rep . You can earn up to four quarters of coverage each year. In order to be fully insured for Social Security Disability purposes, you must have earned at least one quarter of coverage per year for each year since you turned 21 years old. A minimum of six quarters of coverage is needed to be fully insured at any age so maybe Six quarters, at least according to SSD .
Hope I helped or shed some light !.
7 0
3 years ago
Write this ratio 1:3.5 in the form p:q where p and q are whole numbers
Orlov [11]

We have to express the ratio 1 : 3.5 in the form p:q where p and q are whole numbers.

Consider the ratio of 1 and 3.5,

1 : 3.5 = \frac{1}{3.5}

= \frac{10}{35}

Reducing the above fraction to its lowest form.

So, we get \frac{10}{35}=\frac{2}{7}

Therefore, the ratio 1 : 3.5 is expressed as \frac{2}{7}

where 2 and 7 are the whole numbers.

4 0
3 years ago
A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc
aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0
3 years ago
1. Sum of n terms the series:
tensa zangetsu [6.8K]

Step-by-step explanation:

a. 246,913,578

2+22+222+2,222+22,222+222,222+2,222,222+22,222,222+222,222,222

b. 0.3+0.33+0.333+0.3333+0.33333+0.333333+0.3333333+0.33333333+0.333333333 =2.962962963

5 0
3 years ago
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