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first determine the equation. KHP is a monoprotic acid, so it reacts with NaOH in a 1:1 ratio.
<span>a) HKC8H4O4 + NaOH → NaKC8H4O4 + H2O </span>
<span>This allows you to calculate the molarity of NaOH, from the equation V1M1n2 = V2M2n1 </span>
<span>Molarity times volume will give you the number of moles of acid. You can work this out by dividing the mass used by the molar mass. For this question, you will have 1.0115/204.2285 moles KHP, so this value can be substituted for V1M1 in the equation. You need 38.46 mL of NaOH to titrate all the acid, so this will be V2. Now you find M2. </span>
<span>b) 1.0115/204.2285 × 1 = 38.46 × M2 × 1, so M2 = 0.0001288M </span>
<span>Now go on to part 3. Here, you use a similar calculation. The acid and base react in a 1:1 ratio, so n1 = n2 = 1. M2 = 0.1905 and V2 = 25.62. V1M1 will be calculated. </span>
<span>V1M1 × 1 = 25.62×0.0001288×1 = 0.003299856 </span>
<span>Now mass divided by molar mass = V1M1, so molar mass = mass/V1M1. </span>
<span>1.2587/0.003299856 = 381.44 g/mol</span>
<span>IT's Easy The total electrons for the ion Ni^2+ is 26. The +2 charge is the same as saying it lost two of its electrons. Nickel in its standard form has 28 electrons</span>
it's 500kg
Explanation:
I did this I hope this helps
It's observation and a hypothesis.
Answer:
In writing the electron configuration for nitrogen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for N goes in the 2s orbital. The remaining three electrons will go in the 2p orbital. Therefore the N electron configuration will be 1s22s22p3.
Explanation:
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