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laila [671]
3 years ago
10

Given that WXYZ is a rectangle and ZY=2x + 3, and WX=x +4, then WX=

Mathematics
2 answers:
omeli [17]3 years ago
5 0

Answer:

7

Step-by-step explanation:

Snowcat [4.5K]3 years ago
4 0

Answer:

WX = 5

Step-by-step explanation:

2x + 3 = x + 4

x = 1

WX = 2(1) + 3 = 5

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Write the number that has one unit 3 hundreds 8 thousands and 6 tens of thousands
ValentinkaMS [17]

Answer:

i believe it's   .0386

Step-by-step explanation:

3 0
3 years ago
A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P(S) = 0.19. It has also d
Rom4ik [11]
P(LC / S) = P(S intersect LC) / P(S)
P(S intersect LC) = P(S)*P(LC / S) = 0.19 * 0.158 = 0.03
8 0
3 years ago
Find the accumulated value of an investment of $14,000 at 10% compounded semiannually for 11 year
kifflom [539]

Given:

Principal = $14000

Rate of interest = 10% compounded semiannually.

Time = 11 years.

To find:

The accumulated value of the given investment.

Solution:

Formula for amount or accumulated value after compound interest is:

A=P\left(1+\dfrac{r}{n}\right)^{nt}

Where, P is the principal values, r is the rate of interest in decimal, n is the number of times interest compounded in an year and t is the number of years.

Compounded semiannually means interest compounded 2 times in an years.

Putting P=14000,r=0.10,n=2,t=11 in the above formula, we get

A=14000\left(1+\dfrac{0.10}{2}\right)^{2(11)}

A=14000\left(1+0.05\right)^{22}

A=14000\left(1.05\right)^{22}

A\approx 40953.65

Therefore, the accumulated value of the given investment is $40953.65.

8 0
3 years ago
Read 2 more answers
Help within 10 min pleeeeeeeeeease
sineoko [7]
The answer should be 75
4 0
2 years ago
Read 2 more answers
Shelly is 3 years older than Michelle. 4 years ago the sum of their ages was 67. find the age of each person now
Murljashka [212]
If Shelly is 3 years older than Michael and There 67. Michael is 64 and Shelly is 67. Or Michael is 67 and Shelly is 70.

Hope I helped. Have a wonderful day
3 0
3 years ago
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