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sashaice [31]
3 years ago
10

4.0/5.7=1.8/x what is the answer for u smart people

Mathematics
2 answers:
Tema [17]3 years ago
8 0

Answer:

2.565

Step-by-step explanation:

Hope that this helps!

Natali [406]3 years ago
6 0

Answer:

here you go

Step-by-step explanation:

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Which is equivalent to (3 + 2i)(5 + i)?
zepelin [54]
(3 + 2i)(5 + i)
15 + 3i + 10i + 2i^2
15 + 13i - 2
13 + 13i
5 0
3 years ago
Which of the following functions are homomorphisms?
Vikentia [17]
Part A:

Given f:Z \rightarrow Z, defined by f(x)=-x

f(x+y)=-(x+y)=-x-y \\  \\ f(x)+f(y)=-x+(-y)=-x-y

but

f(xy)=-xy \\  \\ f(x)\cdot f(y)=-x\cdot-y=xy

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.



Part B:

Given f:Z_2 \rightarrow Z_2, defined by f(x)=-x

Note that in Z_2, -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular f(x)=x

f(x+y)=x+y \\  \\ f(x)+f(y)=x+y

and

f(xy)=xy \\  \\ f(x)\cdot f(y)=xy

Therefore, the function is a homomorphism.



Part C:

Given g:Q\rightarrow Q, defined by g(x)= \frac{1}{x^2+1}

g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1}  \\  \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.



Part D:

Given h:R\rightarrow M(R), defined by h(a)=  \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)

h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\  \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)

but

h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\  \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.



Part E:

Given f:Z_{12}\rightarrow Z_4, defined by \left([x_{12}]\right)=[x_4], where [u_n] denotes the lass of the integer u in Z_n.

Then, for any [a_{12}],[b_{12}]\in Z_{12}, we have

f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\  \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)

and

f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)

Therefore, the function is a homomorphism.
7 0
3 years ago
Please answer this i really understand this at all its so hard:((
vlabodo [156]

Step-by-step explanation:

25x ratio

stay safe and wear mask

5 0
2 years ago
Please answer! Explain all steps!
MatroZZZ [7]
We will be using the formulas:
speed=distance/time
time=distance/speed
distance=speed×time
First let's find out Diane's rate of swimming. We can measure this by finding the slope (y/x) of a given coordinate on the graph. One point is (10,15), so you do 15/10=1.5m/s
Now for Rick's rate of swimming, just take a pair of values from the table. 12.5/10=1.25m/s
By the way m/s is metres per second for this
So at a constant speed of 1.5m/s, Diane swam 150m in 150/1.5= 100 seconds, or 1 minute 40 seconds
And at a constant speed of 1.25m/s, Rick swam 150m in 150/1.25= 120 seconds, or 2 minutes.
So the difference between their two times is 20 seconds
7 0
3 years ago
Read 2 more answers
A canoe traveled Downstream with the current and went a distance of 15 miles in three hours. On the return trip, the canoe trave
coldgirl [10]

Answer:

1 mile/hr

Step-by-step explanation:

Let the Speed of the boat still in water = a

Speed of the current = b

We know from this formula that speed = distance/time

Hence,

A canoe traveled Downstream with the current and went a distance of 15 miles in three hours.

Downstream = a + b = 15/3

a + b = 5 .........Equation 1

On the return trip, the canoe traveled Upstream against the current. It took 5 hours to make the return trip.

Upstream = a - b = 15/5

a - b = 3 ..............Equation 2

Combining both Equation together

a + b = 5 .........Equation 1

a - b = 3 ..............Equation 2

Subtracting Equation 2 from Equation 1

2b = 2

b = 2/2

b = 1miles/hr

Since b = speed of the current which can also be called rate of the current, the rate of the current = 1 miles/hr

4 0
3 years ago
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