Answer:
MgCO₃
Explanation:
From the question given above, we obtained:
MgF₂ + Li₂CO₃ —> __ + 2LiF
The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:
MgF₂ (aq) —> Mg²⁺ + 2F¯
Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯
MgF₂ + Li₂CO₃ —>
Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯
MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF
Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:
MgF₂ + Li₂CO₃ —> __ + 2LiF
MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF
Therefore, the missing part of the equation is MgCO₃
You would find the highest pressure at the bottom
Answer: Option (b) is the correct answer.
Explanation:
The elements which have excess or deficiency of electrons will react readily.
Atomic number of Mn is 25 and electronic configuration of 
is [Ar]
. This configuration is stable.
Atomic number of Cr is 24 and electronic configuration of 
is [Ar]
. This configuration is not stable.
Atomic number of Fe is 26 and electronic configuration of 
is [Ar]
. This configuration is stable.
Atomic number of Cu is 29 and electronic configuration of 
is [Ar]
. This configuration is not stable.
Atomic number of Al is 13 and electronic configuration of Al is 
. This configuration is not stable.
Atomic number of Ba is 56 and electronic configuration of 
is [Kr]
. This configuration is stable.
Atomic number of Mg is 12 and electronic configuration of 
is 
. This configuration is stable.
Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]
. This configuration is stable.
Thus, we can conclude that out of the given options, only Fe and reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.
