Answer:
1. NO and Br₂
2. 77
3. 8.8
Explanation:
Let's consider the following reaction.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
The equilibrium constant for this reaction is:
![Kc_{1}=\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]} =1.3 \times 10^{-2}](https://tex.z-dn.net/?f=Kc_%7B1%7D%3D%5Cfrac%7B%5BNOBr%5D%5E%7B2%7D%7D%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%20%3D1.3%20%5Ctimes%2010%5E%7B-2%7D)
1. At this temperature does the equilibrium favor NO and Br₂, or does it favor NOBr?
Since Kc₁ < 1, the reactants are favored, that is, NO and Br₂.
2. Calculate Kc for 2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
The equilibrium constant is:
![Kc_{2}=\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}} =\frac{1}{Kc_{1}} =77](https://tex.z-dn.net/?f=Kc_%7B2%7D%3D%5Cfrac%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E%7B2%7D%7D%20%3D%5Cfrac%7B1%7D%7BKc_%7B1%7D%7D%20%3D77)
3. Calculate Kc for NOBr(g) ⇄ NO(g) + 1/2 Br₂(g)
The equilibrium constant is:
![Kc_{3}=\frac{[NO][Br_{2}]^{1/2} }{[NOBr]} =\sqrt{\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}}} =\sqrt{Kc_{2}} =8.8](https://tex.z-dn.net/?f=Kc_%7B3%7D%3D%5Cfrac%7B%5BNO%5D%5BBr_%7B2%7D%5D%5E%7B1%2F2%7D%20%7D%7B%5BNOBr%5D%7D%20%3D%5Csqrt%7B%5Cfrac%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E%7B2%7D%7D%7D%20%3D%5Csqrt%7BKc_%7B2%7D%7D%20%3D8.8)
Answer:
3.59 moles
Explanation:
Hopefully this helps! :)
Mark as brainliest if right!
Yes it could, but you'd have to set up the process very carefully.
I see two major challenges right away:
1). Displacement of water would not be a wise method, since rock salt
is soluble (dissolves) in water. So as soon as you start lowering it into
your graduated cylinder full of water, its volume would immediately start
to decrease. If you lowered it slowly enough, you might even measure
a volume close to zero, and when you pulled the string back out of the
water, there might be nothing left on the end of it.
So you would have to choose some other fluid besides water ... one in
which rock salt doesn't dissolve. I don't know right now what that could
be. You'd have to shop around and find one.
2). Whatever fluid you did choose, it would also have to be less dense
than rock salt. If it's more dense, then the rock salt just floats in it, and
never goes all the way under. If that happens, then you have a tough
time measuring the total volume of the lump.
So the displacement method could perhaps be used, in principle, but
it would not be easy.
Answer: Food production industry
Explanation:
Cooling is a process used mainly to reduce the temperature of food to either enter a different process or for storage purposes.
The temperature reached by the cooling process is usually between -1 and 8 degrees celcius.
