D = m / V
d = 1300 g / 743 cm³
d = 1.749 g/cm³
laboratory stock solution is 1.50 M NaOH. Calcul. Show transcribed image text A laboratory stock solution is 1.50 M NaOH. Calculate the volume of this stock solution that would be needed to prepare 300. ml
Answer:
18.2784 g
Explanation:
First we <u>convert 180 lb to kg</u>:
- 180 lb * 0.453 kg / lb = 81.6 kg
Now we <u>calculate the mass of antibiotic taken in one day</u>:
- 8.0 mg/kg * 81.6 kg = 652.8 mg
Given that it is taken twice daily, <em>in one day the person would take (652.8 * 2) 1305.6 mg</em>. In grams that mass would be:
- 1305.6 mg / 1000 = 1.3056 g
Finally we multiply those 1.3056 daily grams by the 14 days in two weeks:
- (1.3056 g) * 14 = 18.2784 g
No that is why I am asking for help
The answer is :
Nickel II carbonate octahydrate
The explanation:
-when Ni is the symbol of Nickel.
and CO3 is the symbol of carbonate group.
and both have 2 valence so, it will be write 2:2 = 1:1 → NiCO3 named Nickel caronae.
and any compound contain H2O will be named Hydrate and here we have 8 H2O so, i will e named octa (because of his 8 ) octahydrate
so, the compound will be Nickel II carbonate octahydrate