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2 years ago

11

What are the 3 receptors

1 answer:

Nikolay [14]2 years ago

7 0

Answer:

Where’s the image?

Explanation:

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How many moles of disulfur decafluoride are present in 3.99 x 104 molecules of this compound? moles

arsen [322]

<u>Answer:</u> The number of moles of disulfur decafluoride is $6.62\times 10^{-20}$

<u>Explanation:</u>

We are given:

Number of disulfur decafluoride molecules = $3.99\times 10^4$

According to mole concept:

$6.022\times 10^{23}$ number of molecules are contained in 1 mole of a compound.

So, $3.99\times 10^4$ number of molecules will be contained in = $\frac{1mol}{6.022\times 10^{23}}\times 3.99\times 10^{4}=6.62\times 10^{-20}mol$ of disulfur decafluoride.

Hence, the number of moles of disulfur decafluoride is $6.62\times 10^{-20}$

6 0

3 years ago

Write a nuclear equation for the beta decay of Promethium-165

padilas [110]

Answer:

see your answer in pic

Explanation:

4 0

3 years ago

What are two ways to describe concentration? How do they differ from one another?

adell [148]

Answer:

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3 years ago

Read 2 more answers

a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what

jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure, measured in kilopascals.

$V$ - Volume, measured in liters.

$n$ - Molar quantity, measured in moles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

$\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}}$ (2)

Where:

$P_{1}$ , $P_{2}$ - Initial and final pressure, measured in kilopascals.

$V_{1}$ , $V_{2}$ - Initial and final volume, measured in liters.

$T_{1}$ , $T_{2}$ - Initial and final temperature, measured in Kelvin.

If we know that $P_{1} = 121\,kPa$ , $P_{2} = 202\,kPa$ , $V_{1} = 2.7\,L$ , $T_{1} = 288\,K$ and $T_{2} = 303\,K$ , the final volume of the gas is:

$V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}$

$V_{2} = 1.702\,L$

The gas will occupy a volume of 1.702 liters.

6 0

3 years ago

Why is potassium less reactive than silver

Reika [66]

Because potassium is a gas that can evolve

3 0

3 years ago