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Bas_tet [7]
4 years ago
15

What might law enforcement do to reduce attempts at deception when gaining a handwriting sample?

Chemistry
1 answer:
Anarel [89]4 years ago
3 0
In order to decrease the chances of deception in acquiring a handwriting sample, what the law enforcement do is that, they ask they person to write as little as possible, write the passage only once and also gather the material that consist some of the similar words and phrases as the suspected document. Answer for this would be all of the above.
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When titanium (II) nitride forms an ionic compound, what is the chemical formula of the compound?
jek_recluse [69]

Answer:

When titanium (II) nitride forms an ionic compound, TiN is the chemical formula of the compound.

4 0
3 years ago
When determining the specific heat from a given metal in a calorimeter the mass of the water remains constant, but the mass of t
alexandr1967 [171]
The heat is hotter than cold                                                                                                                                                                                  
6 0
4 years ago
Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
AnnZ [28]

<u>Answer:</u> The limiting reagent is oxygen gas.

<u>Explanation:</u>

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For propane:</u>

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol

  • <u>For oxygen:</u>

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{75.0g}{32g/mol}=2.34mol

The chemical equation for the combustion of propane follows:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = \frac{1}{5}\times 2.34=0.468mol of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

3 0
3 years ago
Yes or no: will a precipitate form when solutions of ba(no3)2 and koh are mixed?
lakkis [162]
No, a precipitate will not form when barium nitrate, Ba(NO3)2, reacts with potassium hydroxide, KOH, in aqueous solution because both products are soluble in water.
3 0
3 years ago
What type of reaction is this.... CH2(g)+02(g)
oee [108]

Combustion

Explanation:

This reaction is called a combustion reaction. It is very peculiar to reactions involving hydrocarbons.

In such reactants, oxygen gas is used as a reactant. It combines with fuel usually the hydrocarbon to produce heat and light energy.

For the combustion of most hydrocarbons, water and carbon dioxides are usually the product.

        2CH₂   +   3O₂  →   2CO₂   +  2 H₂O

learn more:

Combustion brainly.com/question/11089002

#learnwithBrainly

6 0
3 years ago
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