Question

MATH who can do this

Answer 1

Answer/Step-by-step explanation:

Recall the acronym SOHCAHTOA. This is what we would apply as appropriate in each case.

8. θ = 40°

Opp = m

Adj = 20

Thus, apply TOA

Tan (θ) = opp/adj

Plug in the values

Tan (40) = m/20 (equation)

20×Tan(40) = m

m = 16.7820

9. θ = 22°

Hyp = w

Adj = 18

Thus, apply CAH

Cos (θ) = adj/hyp

Plug in the values

Cos 22 = 18/w (equation)

w×cos 22 = 18

w = 18/(cos 22)

w = 19.4136

10. θ = 35°

Hyp = 55

Opp = x

Thus, apply SOH

Sin θ = opp/hyp

Plug in the values

Sin 35 = x/55 (equation)

55×sin 35 = x

x = 31.5467

11. θ = 33°

Hyp = 19

Adj = x

Thus, apply CAH

Cos θ = adj/hyp

Plug in the values

Cos 33 = x/19 (equation)

19×cos 33 = x

x = 15.9347

12. θ = 17°

Opp = 7

Hyp = x

Thus, apply SOH

Sin θ = opp/hyp

Plug in the values

Sin 17 = 7/x (equation)

x×sin 17 = 7

x = 7/(sin 17)

x = 23.9421

13. θ = 40°

Opp = 15

Adj = x

Thus, apply TOA

Tan θ = opp/adj

Plug in the values

Tan 40 = 15/x (equation)

x×Tan 40 = 15

x = 15/(Tan 40)

x = 17.8763