I suppose the integral is

The integration region corresponds to a sector of a cirlce with radius 5 subtended by a central angle of π/4 rad. We can capture this region in polar coordinates by the set

Then
,
, and
. So the integral becomes

im sorry I want to help but it wouldnt load :'(
2.; it’s the easiest, fastest, and simplest way to get to your factors
3.0 NOT SURE IF ITS CORRECT
Since it is a parallelogram cente at point T,
then the measure of PT is equal to the measure of TR. And the measure of QT is
equal to the measure of TS.
PT = TR
a + 4 = 2a
4 = 2a -a
a = 4
PT = TR = 8 units
QT = TS
b = 2b -3
3 = 2b – b
b = 3
<span>QT = TS = 3 units</span>