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never [62]
3 years ago
12

Tan^2A -sin^2A=sin^2a Tan^2A​

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Using the identity

sin²A = 1 - cos²A , tanA = \frac{sinA}{cosA}

Consider the left side

tan²A - sin²A

= \frac{sin^2A}{cos^2A} - sin²A

\frac{sin^2A-sin^2Acos^2A}{cos^2A}

= \frac{sin^2A(1-cos^2A)}{cos^2A}

= \frac{sin^2A.sin^2A}{cos^2A}

= sin²A × \frac{sin^2A}{cos^2A}

= sin²A . tan²A

= right side , thus verified

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