Four of them pass a point every second.
The new magnitude of the force of attraction will be 6 times the original force of attraction
<h3>How to determine the initial force </h3>
- Mass 1 = m₁
- Mass 2 = m₂
- Gravitational constant = G
- Distance apart = r
- Initial force (F₁) = ?
F = Gm₁m₂ / r²
F₁ = Gm₁m₂ / r²
<h3>How to determine the new force </h3>
- Mass 1 = 2m₁
- Mass 2 = 3m₂
- Gravitational constant = G
- Distance apart (r) = r
- New force (F₂) =?
F = Gm₁m₂ / r²
F₂ = G × 2m₁ × 3m₂ / r²
F₂ = 6Gm₁m₂ / r²
But
F₁ = Gm₁m₂ / r²
Therefore
F₂ = 6Gm₁m₂ / r²
F₂ = 6F₁
Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction
Learn more about gravitational force:
brainly.com/question/21500344
#SPJ1
Answer:
0.43 m
Explanation:
Angle of incident and angle of reflection is same.
tan Θh = L' / x (eye)
L' = Length of the window
x (eye) = Distance of the mirror from the eye
tan Θh = L / (x (eye) + xw)
xw = Distance of the mirror from the window
L'/ x (eye) = L / ( x (eye) + xw)
L' = L*x (eye) / ( x (eye) + xw)
L' = (2*0.5) / (0.5 + 1.8)
L' = 0.43 m
Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.
That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.
