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mina [271]
3 years ago
12

One event in a high school track meet is the 400 meter run. If the runners of the 4oo meter event start and end at the same loca

tion, what is their DISPLACEMENT?
Physics
1 answer:
ohaa [14]3 years ago
6 0
In physics, displacement is a physical quantity that is used to describe the overall change in the position of an object/person.
In other words, it describes how far you are from your initial position.

In the given problem, the initial position is the same as the final position. This means that overall change in position is zero, which also means that the difference between the final and initial positions is zero.

Based on the above, the displacement is zero.
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Can the boiling point of water exceed 100c
lisabon 2012 [21]
Superheated water is liquid water under pressure at temperatures between the usual boiling point, 100c (212 F ) and the critical temperature , 374 C (705F) . It is also known as “subcritical water”
Or “pressurized hot water”.
6 0
3 years ago
A father pushes his child on a swing. He pushes with a force of 20 N or a distance of 1 m, with the force always maintained para
Firlakuza [10]

Answer:

20 Joules

Explanation:

Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.

Therefore, we have;

Work done = Force x distance

i.e   Wd = Fs

Given that: F = 20 N and s = 1 m, then;

Wd = 20 N x 1 m

     = 20 Nm

The work done by the father is 20 Joules(Nm).

7 0
3 years ago
Hardness and density are physical properties.<br> a. True<br> b. False
antiseptic1488 [7]
a . true hardness and density are physical properties
7 0
3 years ago
Read 2 more answers
A convex lens bulges outward in its center. and it refracts light rays towards its center. Which represents a convex lens? A) A
Mila [183]

Answer:

Its A

Explanation:

The lens bulges outward in its center, like reading glasses.

4 0
3 years ago
Read 2 more answers
A firefighting crew uses a water cannon that shoots water at 25.0 m/s at a fixed angle of 53.0° above the horizontal. The fire-f
zysi [14]

Answer:

8.8 m and 52.5 m

Explanation:

The vertical component and horizontal component of water velocity leaving the hose are

v_v = vsin(\alpha) = 25sin(53^0) = 25*0.8 = 19.97 m/s

v_h = vcos(\alpha) = 25cos(53^0) = 25*0.6 = 15 m/s

Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level

s = v_vt + gt^2/2

10 = 19.97t - 9.8t^2/2

4.9t^2 - 19.97t + 10 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{19.9658877511823\pm \sqrt{(-19.9658877511823)^2 - 4*(4.9)*(10)}}{2*(4.9)}

t= \frac{19.9658877511823\pm14.24}{9.8}

t = 3.49 or t = 0.58

We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down

t is also the times it takes to travel across horizontally. We can use this to compute the horizontal distance between the fire-fighters and the building

s_1 = v_ht_1 = 15*0.58 = 8.8 m

s_2 = v_ht_2 = 15*3.49 = 52.5m

8 0
3 years ago
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