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Kitty [74]
2 years ago
14

A 10kg oil is heated by a source of heat that supplies 800J of heat every minute. Calculate The heat added to oil after 30 minut

es.​
Physics
1 answer:
goblinko [34]2 years ago
4 0

Answer:

4,200 joules per kilogram per degree Celsius

Explanation:

The specific heat capacity of a material is the energy required to raise one kilogram (kg) of the material by one degree Celsius (°C). The specific heat capacity of water is 4,200 joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C.

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Answer:

Diabetic Retinopathy is a form of diabetes that affects the eyes. It can be caused by damage to the retinas, and can cause permanent damage to the eyes, and even blindness. Initially the patient is asymptomatic and become more visibly affected in later stages. It can be treated if caught early, or in mild cases.

Explanation:

4 0
2 years ago
The mass of a moving object increases, but its speed stays the same. What happens to the kinetic energy of the object as a resul
ozzi
The correct answer is 
B It increases.

In fact, the kinetic energy of a moving object is given by
K= \frac{1}{2}mv^2
where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.
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3 years ago
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Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all. Joffre
lana [24]

Answer:

R.E.T.A.R.D.A.T.I.O.N

Explanation:

It won't let me spell it normal

7 0
3 years ago
Một chiếc thuyền có tốc độ 15 km / h trong nước tĩnh lặng đi 30 km về phía hạ lưu và trở lại trong tổng cộng 4 giờ 30 phút. Tốc
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3 0
3 years ago
7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
Nesterboy [21]

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

where

M_m = 18.02 g/mol is the molar mas

m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

6 0
3 years ago
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