Answer:
Instable behavior.
Explanation:
The checkpoints currently behaving instable in sally cancer cells because mutants show genetic instability so this instability is the cause of cancer disease. Two checkpoints are sensitive to DNA damage, one occur before mitosis cell division and the other occur before replication of DNA. So damage occur in these two check points leads to instable behavior of cancer cells.
The amount of glucose in each ml of their blood will be 0.00138 g.
<h3>Blood glucose concentration</h3>
The concentration of glucose in the person's blood is 1.38%.
This means that there is 1.38 g of sugar per Liter of blood.
1 Liter of blood contains 1.38 g of glucose, and there is 1000 mL in 1 Liter of blood.
1000 mL contains 1.38 g
1 ml contains = 1.38 x 1 / 1000 = 0.00138 g
This means 0.00138 g of glucose will be present in every 1 mL of the person's blood.
More on blood glucose can be found here: brainly.com/question/8394646
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Answer:
Explanation: 1) Individual who is bald but neither parents has a widow's peak: As having a peak is dominant and the individual is bald with parents that doesn't have the trait, the genotype is recessive, in the case ww;
2) Individual has a widow's peak: The individual's genotype can be WW, homozygous for the trait or Ww, heterozygous for the trait, depending on the genotype of the parents;
3) Individual can't roll their tongue: Being able to roll the tongue is a dominant characteristics, so if the individual can't roll their tongue means the genotype is recessive. But, there is little evidence that this trait is dominant or inheritable;
4) Individual has a widow's peak but their mother does not: In this case, the genotype of the individual is heterozygous (Ww), because the mother is recessive (ww) and the offspring has the trait, so the father must have had it;
5) If an individual does not have a widow's peak (ww), which genotype would be impossible? If this individual crosses over with another individual with the same trait, their children will be all recessive for widow's peak (ww), so there is no possibility of an offspring with the trait;
If the initial individual crosses over with an individual with widow's peak, two possiblities can occur:
- If the crossover is with an individual homozygous for the trait (WW): all their children will have widow's peak with genotype Ww. So, the possibility of not having the peak is 0;
- If the crossover is with an individual heterozygous for the trait (Ww), there will be a probability of 25% for the children to have genotype WW, a probability of 50% for the offspring to be heterozygous (Ww) and has the trait and probability of 25% to be recessive (ww) and therefore doesn't have the trait;
Answer:
An individual skeletal muscle may be made up of hundreds, or even thousands, of muscle fibers bundled together and wrapped in a connective tissue covering. Each muscle is surrounded by a connective tissue sheath called the epimysium. Fascia, connective tissue outside the epimysium, surrounds and separates the muscles.
Explanation:
Answer:
Cytokinesis
Explanation:
It is the first stage
