The transformation set of 
values for function 
is ![[-1,1]](https://tex.z-dn.net/?f=%5B-1%2C1%5D)
this is an interval to which sine function maps.
You can observe that the interval to which 
function maps equals to ![[-2,0]](https://tex.z-dn.net/?f=%5B-2%2C0%5D)
.
So let us take a look at the possible options.
Option A states that shifting up by 
would result in having an interval ![[-1,1]+\frac{\pi}{2}\approx[0.57,2.57]](https://tex.z-dn.net/?f=%5B-1%2C1%5D%2B%5Cfrac%7B%5Cpi%7D%7B2%7D%5Capprox%5B0.57%2C2.57%5D)
which is clearly not true that means A is false.
Let's try option B. Shifting down by 
to get would mean that has a transformation interval of ![[-1,1]-1=[-2,0]](https://tex.z-dn.net/?f=%5B-1%2C1%5D-1%3D%5B-2%2C0%5D)
. This seems to fit our observation and it is correct.
So the answer would be B. If we shift down by one we get , which means that 
and 
.
Hope this helps :)
5,250 millimeters is your answer!
The coordinates of the corners in the scale drawing of the desing are:
H = (2,0)
I = (0,0)
J = (0,4)
K = (2,4)
That makes the lengths of the segments be:
HI = 2 - 0 = 2
JK = 2 - 0 =2
JI = 4 - 0 = 4
KH = 4 - 0 = 4
Now check the segments of the actual cover:
H'I' = 10 - 0 = 10
K'J' = 10 - 0 = 10
J'I' = 16 - 0 = 16
K'H' = 16 - 0 = 16
Now check corresponding segments meet proportionality criterium, which is needed for similarity:
H'I' / HI = 10 /2 = 5
K'J' / KJ = 10 / 2 = 5.
So far we this is fine.
JI / J'I' = 16 / 4 = 4............ then not, the ratio is not the same ratio of the other two segments, which implies that the scale used for the vertical segments is different to the scale used for the horizontal segments, driving to a non similar figure.
Answer: no, because the corresponding sides are not proportional
This is slope!!is it true???????
