Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
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Answer:
B
Step-by-step explanation:
In the case of this distance, trying to imagine 5 x 10^6 is obviously way too ridiculous
The Pythagorean theorem tells you
... a² + b² = c²
so
... a² = c² - b² = 16² - 9² = 256-81 = 175
... a = √175 = √(25·7)
... a = 5√7
Let x = the length of the shorter piece
x+x+16=50in
2x=50-16
2x=34
x=17
Then
x+16=17+16
x+16=33
Subtract 16 from both sides
The lengths are 17in and 33in