Add the KE increase and the work done against friction.
The final velocity is twice the average, or 3.0 m/s
The final KE is (1/2)*25*3^2 = 112.5 J
The friction work done is 6*3.8 = 22.8 J
hope this is correct
Each increase in the prefix is a division by 1000.
Hi Gamingclan4444
Raising the temperature and reducing the volume of the gas will make the pressure of a gas DEFINITELY increase.
Answer: B) or the second option.
Answer:
1.31022×10⁻³⁴ kg
Explanation:
Difference in energies = 1189.4-1115.7 MeV = 73.7 MeV
Convert this energy to Joules
1 MeV = 1.6×10⁻¹⁹ J
73.7 MeV = 73.7×1.6×10⁻¹⁹ J = 117.92×10⁻¹⁹ J
c = Speed of light = 3×10⁸ m/s
From Einstein's equation
E = mc²
∴ Difference in their masses is 1.31022×10⁻³⁴ kg
There is equal number of each type of atom on the reactant and product side.
<u>Explanation:</u>
Conserving mass in a chemical reaction means balancing the conservation of mass through the law and balancing the atoms. There is equal number of each type of atom on the reactant and product side.
There is an equal amount of atoms on both the sides that is the reactant side as well as the product side, it balances the atoms to have a conservation of mass, through the law of conservation of mass.
Using the law of conservation mass, a chemical reaction is balanced and has a conserved mass, when the reactant and the product side contain equal atoms.
