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balu736 [363]
1 year ago
7

A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. How much energy is lost? Group of answer choices 0.5

J 0.88 J 0.29 J 1 J
Physics
1 answer:
bogdanovich [222]1 year ago
3 0

Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J

Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.

<h3>What is gravitational potential energy?</h3>
  • The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.
  • The gravitational potential energy of a body at a height h with respect to the height h will be,

                                          U=mgh

  • Expression for gravitational potential energy loss will be,

                                        E=U_i-U_f

<h3>How to solve the problem?</h3>
  • The total energy before the ball dropped will be,

                 U_i=mgh_i=60*10^-3kg*9.8m/s^2*2m=1.176 J

  • The total energy after when the ball rebounds to 1.5m will be,

                 U_f=mgh_f=60*10^-3kg*9.8m/s^2*1.5m=0.882J

  • The total energy loss will be,

                E=1.176-0.882=0.294J

Thus, we can conclude that, the energy loss will be,0.294J.

Learn more about the gravitational potential energy here:

brainly.com/question/28044692

#SPJ4

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Answer:

Use a faster than normal approach and landing speed.

Explanation

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6 0
3 years ago
What mechanism of energy is transferred by mass motion of fluid from one region of space to another?​
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5 0
2 years ago
1. Space probes have not landed on Pluto yet. Describe three types of information you would collect if you were designing the pr
konstantin123 [22]

Answer:

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Explanation:

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2 years ago
What quantity of heat is needed to convert 1 kg of ice at -13 degrees C to steam at 100 degrees C?
Effectus [21]

Answer:

Heat energy needed = 3036.17 kJ

Explanation:

We have

     heat of fusion of water = 334 J/g

     heat of vaporization of water = 2257 J/g

     specific heat of ice = 2.09 J/g·°C

     specific heat of water = 4.18 J/g·°C

     specific heat of steam = 2.09 J/g·°C

Here wee need to convert 1 kg ice from -13°C to vapor at 100°C

First the ice changes to -13°C from 0°C , then it changes to water, then its temperature increases from 0°C to 100°C, then it changes to steam.

Mass of water = 1000 g

Heat energy required to change ice temperature from -13°C to 0°C

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Liula [17]

Answer:

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b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

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We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

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