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babymother [125]
3 years ago
9

What is the result of a mutation during replication

Physics
2 answers:
Sonbull [250]3 years ago
8 0

The correct answer is A. The strands are different. Hope this helps! :)

ss7ja [257]3 years ago
6 0

Answer:

Its A

Explanation: I took the quiz ewe

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Which question can be used to identify a physical property of an element?
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Answer:C

Explanation:

Do bubbles form when the element is mixed with an acid

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Which of the following is an example of proper movement for a biceps curl?
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<span>i think the answer is : Bend the arm at the elbow with the back straight </span>
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The relationship between two quantities that increase or decrease together is called ___
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<span>The relationship between two quantities that increase or decrease together is called directly proportional.

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3 years ago
A factory worker pushes a 32.0 kgkg crate a distance of 4.0 mm along a level floor at constant velocity by pushing horizontally
Luda [366]

Answer:

a) The force that the worker must apply has a magnitude of 75.317 newtons.

b) The external force does a work of 0.301 joules.

c) The friction force does a work of -0.301 joules.

d) Both normal force and gravity have done a work of 0 joules.

e) The total work done on the crate is 0 joules.

Explanation:

a) As the crate is moving at constant velocity, we know that magnitude of the force done on the crate must be equal to the friction force. Hence, we must use the following formula:

F = \mu\cdot m\cdot g (1)

Where:

F - External force, in newtons.

\mu - Coefficient of kinetic friction, no unit.

m - Mass, in kilograms.

g - Gravity acceleration, in meters per square second.

If we know that \mu = 0.24, m= 32\,kg and g = 9.807\,\frac{m}{s^{2}}, then the external force is:

F = (0.24)\cdot (32\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 75.317\,N

The force that the worker must apply has a magnitude of 75.317 newtons.

b) The direction of the force is parallel to the direction of motion. The work done by this force (W_{F}), in joules, is determined by this formula:

W_{F} = F\cdot \Delta s (2)

Where \Delta s is the distance travelled by the crate, in meters.

If we know that F = 75.317\,N and \Delta s = 0.004\,m, then the work done by the force is:

W_{F} = (75.317\,N)\cdot (0.004\,m)

W_{F} = 0.301\,J

The external force does a work of 0.301 joules.

c) The direction of the friction force is antiparallel to the direction of motion. The work done by this force (W_{f}), in joules, is determined by this formula:

W_{f} = -W_{F} (3)

W_{f} = -0.301\,J

The friction force does a work of -0.301 joules.

d) The direction of the normal force is perpendicular to the direction of motion. Therefore, no work is done due to normal force.

W_{N} = 0\,J

Likewise, no work is done by gravity.

W_{g} = 0\,J

Both normal force and gravity have done a work of 0 joules.

e) The total work is the sum of the works done by the external force and the friction force:

W = W_{F}+W_{f}

W = 0.301\,J - 0.301\,J

W = 0\,J

The total work done on the crate is 0 joules.

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What type of observation is made through interviewing people’s
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Interviewing and observation are two methods of collecting qualitative data as part of research. ... Interviews vary from structured, in which a set list of questions is asked of every interviewee, to unstructured, which is open-ended.

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