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babymother [125]
3 years ago
9

What is the result of a mutation during replication

Physics
2 answers:
Sonbull [250]3 years ago
8 0

The correct answer is A. The strands are different. Hope this helps! :)

ss7ja [257]3 years ago
6 0

Answer:

Its A

Explanation: I took the quiz ewe

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Specialized intermodal tank container which carries refrigerated liquid gases, oxygen, or helium
Nookie1986 [14]
This would be a cryogenic intermodal tank. These are used to store and transport HAZMAT gases that require storage under specific pressure and temperature parameters. Cryogenic Intermodal tanks have pressure of 25 Psi or less. 
8 0
3 years ago
after singing for a few minutes the soloist rejoins the choir a second choir, consist of 90 additional singers then joins in eac
vredina [299]
If the soloist produces "x" decibels and the 10-person choir produces "y" decibels, combined they will produce "x+y" decibels. 

The second choir has 90 additional singers, we base our description on the first choir. If a 10-person choir produces "x+y" decibels, then the 90 person choir produces 10 (x+y) decibels. 
7 0
2 years ago
A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i
attashe74 [19]

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>
  • As per Newton's equation of motion, V= U+at
  • U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

  • So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>
  • As per Newton's equation of motion,

V²-U² = 2aS

  • S= distance covered by the car
  • So, 20²-0=2×2×S=4S

=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

#SPJ1

4 0
1 year ago
a truck was traveling at 16.6 miles per second and accelerates at a rate of 2.0 meters per second squared how much time is requi
Ivan

A truck was traveling at 16.6 miles per second and accelerates at a rate of 2.0 meters per second squared then time is required for the truck to reach a speed of 25 miles per second is 6759 s.

Explanation:

Velocity is defined as the rate of change in displacement while acceleration is defined as the rate of change of velocity. Acceleration may be positive or negative. Acceleration is positive when the velocity of the object is increases and it is negative when velocity of the object is decreases. Negative acceleration is also called deceleration.

Mathematically

a = \frac{(v_{f} - v_{i})}{t}

Where a is the acceleration of the object, v_{f} is the final velocity of the object and  v_{i} is the initial velocity of the object. t is equal to time taken.

Given data:

v_{f} = 25 miles/s

v_{i} = 16.6 miles/s

a = 2.0 m/s²

t = ?

As velocities and acceleration given in different units, So we need to convert to obtain same units. Here we convert unit of acceleration  from m/s² to miles/s².

1 m/s² = 0.000621371192 miles/s²

2 m/s² = 0.00124274238 miles/s²

So,

a = 0.00124274238 miles/s²

Apply formula

a =\frac{v_{f} - v_{i}}{t}

t = \frac{(v_{f} - v_{i})}{a}

t = \frac{(25 - 16.6)}{0.00124274238}

t = 6759 s

Learn more about velocity and acceleration from

brainly.com/question/1192983

#learnwithBrainly

3 0
3 years ago
Can anybody help me please?
vovangra [49]

Answer:

1,2,5

Explanation:

7 0
2 years ago
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