Question

(URGENT) A ball rolls off a ledge. Its velocity is 7.70m/s in a horizontal direction. It falls on the floor 1.60m below the ledge. What is the horizontal distance that it travels while in the air?

Answer 1

Answer:

the horizontal distance is 4.355 meters

Explanation:

The computation of the horizontal distance while travelling in the air is shown below:

Data provided in the question is as follows

Velocity = u = 7.70 m/s

H = 1.60 m

R = horizontal direction

Based on the above information

As we know that

R = u × time

where,

Time = $\sqrt{\frac{2H}{g} }$

So,

= $7.70\times \sqrt{\frac{2\times 1.60}{10} }$

= 4.355 meters

hence, the horizontal distance is 4.355 meters