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mestny [16]
3 years ago
5

Bob is pushing a box across the floor at a constant speed of 1.7 m/s, applying a horizontal force whose magnitude is 70 N. Alice

is pushing an identical box across the floor at a constant speed of 3.4 m/s, applying a horizontal force. a. What is the magnitude of the force that Alice is applying to the box? F = N b. With the two boxes starting from rest, explain qualitatively what Alice and Bob did to get their boxes moving at different constant speeds. a. In order to keep the box moving twice as fast, Alice had to apply a constant force that was twice as large as the force that Bob applied.b. Each initially applied a force bigger than static friction to get the box moving and accelerating, then when the desired final speed was achieved they reduced the force to make the net force zero.
Physics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

a) 70 N, b) b. Each initially applied a force bigger than static friction to get the box moving and accelerating, then when the desired final speed was achieved they reduced the force to make the net force zero.

Explanation:

a) A constant speed means that magnitude of friction force is equal to the magnitude of the external force. The friction force is directly proportional to the normal force, which is equal to the weight of the box. Therefore, the magnitude of the force is 70 N.

b) Alice used initially a greater force to accelerate the box up to needed speed and later reduced the external force to keep speed constant. The right choice is option b.

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disa [49]

The value of v; initial velocity is determined as, v = h/t + gt.

<h3>What is initial velocity of an object?</h3>

The initial velocity of an object is the velocity of the object before the effect of acceleration, which causes the change of velocity.

h = vt - gt²

to solve for v (the initial velocity) we will make v the subject of the formula.

h + gt² = vt

divide both sides of the equation by t

h/t + gt  = v

Thus, the value of v; initial velocity is determined as, v = h/t + gt.

Learn more about initial velocity here: brainly.com/question/19365526

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7 0
1 year ago
A conductor carries a current that is decreasing exponentially with time. The current is modeled as ????=????0????−????/???? , w
Vlad1618 [11]

Answer:

Q=1.42 C

Explanation:

Given that

I=I_oe^{\dfrac{-t}{\tau}}

When t= 0 ,Io = 3 A

τ = Time constant = 0.5 s

I=3e^{-\dfrac{t}{\tau}}

We know that

I=\dfrac{dQ}{dt}

Q=Charge ,I =Current

Q = ∫I.dt

Given that

t= 0 to t= 3τ= 1.5 s

The charge Q

Q=\int_{0}^{1.5}3e^{-\dfrac{t}{0.5}}dt

Q=1.42 C

Therefore charge flow conductor will be 1.42 C.

3 0
3 years ago
A(n) 636 kg elevator starts from rest. It moves upward for 4.5 s with a constant acceleration until it reaches its cruising spee
zmey [24]

Answer:

The average power delivered by the elevator motor during this period is 6.686 kW.

Explanation:

Given;

mass of the elevator, m = 636 kg

initial speed of the elevator, u = 0

time of motion, t = 4.5 s

final speed of the elevator, v = 2.05 m/s

The upward force of the elevator is calculated as;

F = m(a + g)

where;

m is mass of the elevator

a is the constant acceleration of the elevator

g is acceleration due to gravity = 9.8 m/s²

a = \frac{v-u}{t} \\\\a = \frac{2.05 -0}{4.5} \\\\a = 0.456 \ m/s^2

F = (636)(0.456 + 9.8)

F = (636)(10.256)

F = 6522.816 N

The average power delivered by the elevator is calculated as;

P_{avg} = \frac{1}{2} (Fv)\\\\P_{avg} = \frac{1}{2} (6522.816 \ \times \ 2.05)\\\\P_{avg} = 6685.89 \ W\\\\P_{avg} =  6.68589 \ kW\\\\P_{avg} =  6.686 \ k W

Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.

3 0
2 years ago
What mass will accelerate at 3 m/s² when a net force of 150 N acts on it?
vodomira [7]

Answer:

\huge\boxed{\sf m = 50\ kg}

Explanation:

<h3><u>Given data:</u></h3>

Acceleration = a = 3 m/s²

Force = F = 150 N

<h3><u>Required:</u></h3>

Mass = m = ?

<h3><u>Formula:</u></h3>

F = ma

<h3><u>Solution:</u></h3>

Put the givens in the formula

150 = m (3)

Divide 3 to both sides

150/3 = m

50 kg = m

m = 50 kg

\rule[225]{225}{2}

7 0
1 year ago
A kind of variable that a researcher purposely changes in investigation is
Ugo [173]

Answer:

independent variable

Explanation:

3 0
3 years ago
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