Question

A quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, to the nearest hundredth? please help

Answer 1

Answer:

7569.36

Step-by-step explanation:

Given that a quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, 

First convert 1.25 days to hours

1.25 × 24 = 30 hours

Using exponential equation

N = No ( 1 - R% )^t

Where N = new value of the quantity

No = initial value

R = rate

t = time

N = 7800 ( 1 - 0.001 )^30

N = 7800 ( 0.999 )^30

N = 7800 × 0.97043

N = 7569.36154

N = 7569.36 to the nearest hundredth.

Therefore, the value of the quantity after 1.25 days is 7569.36

Answer 2

Answer:8176.99

Step-by-step explanation: