Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)
Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84
The least number of pairs of skates they need to rent each day to make their minimum is 6.
Answer:
76w + 17
Step-by-step explanation:
7 ( 5 + 4w ) + 6 ( 8w - 3 )
= 7 ( 5 ) + 7 ( 4w ) + 6 ( 8w ) - 6 ( 3 )
= 35 + 28w + 48w - 18
= 28w + 48w + 35 - 18
= 76w + 17
Answer:
387 km
Step-by-step explanation:
The length of AC, b can be obtained using the cosine rule ; using the cosine relation:
b² = a² + c² - 2ac CosB
b² = 250² + 185² - 2(250*185) Cos125
b² = 62500 + 34225 - 92500 * −0.573576
b² = 96725 + 53055.820
b² = 149780.82
b = sqrt(149780.82)
b = 387.01527
b = 387 km (nearest whole number)
Answer:
1/26
Step-by-step explanation:
1 out of 13 would be equal to the amount of cards that would be a jack.
But you also have to take into regards the coin flip 50%chance so you would just could what the number is divided by to get the right answer. Since out come could be tails or head instead of just being one for sure for example.
