This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
Learn more:
Option C: Sulfur Dioxide is the answer
Hope this helps
Copper is an brown-orange color which it's atomic number is 29. With high thermal and electricity conductivity with it's smooth surface.
The answer would be c as the cart is not in motion therefor ruling out kinetic and it is completely at rest making all of it energy potential
since both the jars are kept at the same temperature the vapor pressure will be same in both the cases.
