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leonid [27]
3 years ago
10

If you accidentally spill phosphorus-32 onto your shoe, how long would it take before 99.9% of the radioactive material has deca

yed so that you can safely wear the shoes again?
Chemistry
1 answer:
GenaCL600 [577]3 years ago
3 0
Probably a few months or years I would think. If I am wrong Sorry.
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Question 4, can you give me the rule for naming these?
Scorpion4ik [409]

3 ethyl, 4 methylheptane. The compound is named by first identifying the longest carbon chain in the structure. in this case the chain has seven carbon atoms thus the prefix hept-.

Next you identify the substituent groups attached to the long carbon chain and name them from the lowest value of the integer assigned to the carbon atoms from either side. From the right, the ethyl group is attached to carbon number 3 while from the left, the methyl group is attached to carbon number 4. We therefore start with the right and name the attached groups first, including the carbon atoms to which they are attached.

Then we also take into consideration the highest number of bonds between the carbon atoms which is one from the question. Thus the suffix -ane is added if a maximum of one bond, -ene,if two bonds and -yne if three bonds.

3 0
3 years ago
The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti
maksim [4K]

The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
  • Half-life (t½) = 4 days
  • Time (t) = 4 weeks = 4 × 7 = 28 days
  • Number of half-lives (n) =?

n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 7
  • Amount remaining (N)=?

N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>
  • Original amount (N₀) = 100 g
  • Amount remaining (N)= 0.78125 g
  • Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

7 0
2 years ago
How does changing the amount of one substance affect a mixtures identity and a compounds identity iscience?
pychu [463]

Explanation:

A compound is defined as follows.

  • Compounds are pure substance.
  • The atoms bonded in a compound are in specific proportion.
  • A compound is formed by chemical combination.
  • For a compound, melting point and boiling point is defined.

A mixture is defined as follows.

  • Mixtures are impure substance.
  • The bonded atoms in a mixture are in any proportion.
  • A mixture is formed by physical combination.
  • For a mixture, melting point and boiling point is not defined.

On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures  as atoms can be bonded in any proportion in a mixture.

5 0
2 years ago
Read 2 more answers
How many joules are needed to warm 675 grams of water (specific heat= 4.186 J/g degrees Celsius) from 12 degrees Celsius to 85 d
Naya [18.7K]
85-12 = 73 degrees needed
4.186 J/degree Celsius, so 
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J

2.06 x 10^5 J are needed
3 0
3 years ago
Read 2 more answers
How many moles of water can be obtained from the reaction of 4 moles of O2?
Yuliya22 [10]

Answer: 8moles

Explanation:

The reaction below shows the formation of 2 moles of water from 2 moles of hydrogen and 1 mole of oxygen respectively.

2H2(g) + O2 (g) --> 2H2O(l)

So, if 1 mole of O2 produce 2 mole of H2O

4 moles of O2 will produce Z mole of H2O

To get the value of Z, cross multiply

1 x Z = 4 x 2

Z = 8

So, the equation will be 8H2(g) + 4O2 (g) --> 8H2O(l)

Thus, 4 moles of O2 will produce 8moles of H2O .

6 0
3 years ago
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