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Volgvan
3 years ago
7

Kim estimates that the faucet in her kitchen drips at the rate of 1 drop every 2 seconds. Erik wants to know how many times the

faucet drips in a week.
Mathematics
1 answer:
gregori [183]3 years ago
3 0
I think it would be 302400
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Determine by inspection (i.e., without performing any calculations) whether a linear system with the given augmented matrix has
devlian [24]

Answer:

Infinitely Many Solutions

Step-by-step explanation:

Given

\left[\begin{array}{cccccc}1&2&3&4&5&6\\7&6&5&4&3&2\\8&8&8&8&8&8\end{array}\right]

Required

Determine the type of solution

From the matrix, we have:

3 non-zero rows and 5 variables (the last column is the result)

When the number of variables is more than the number of non-zero rows, then such system has infinitely many solutions

i.e.

Variables > Non\ zero\ rows

5 > 3

8 0
3 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
Mary has a recipe for banana bread. She uses 712 cups of flour to make 3 loaves of banana bread. Andrea will follow the same rec
Softa [21]
237.3f= 1b. Explanation: is 712/3(237.3) so 1b is 237.3f
6 0
3 years ago
Read 2 more answers
Let g(x) = 9x + 24<br> find g(3)<br> Let g(x)=9x+24, find g(3).
sasho [114]

Answer:

51

Step-by-step explanation:

Plug in 3 as x into the function:

g(x) = 9x + 24

g(3) = 9(3) + 24

g(3) = 27 + 24

g(3) = 51

6 0
3 years ago
Read 2 more answers
Can someone help me out on questions 6, 7, and 8?
PolarNik [594]
For #6 draw a triangle between the points and find the middle by drawing the lines to the middle. There should be triangles within the triangles which finding the hypotenuses should be the same.
6 0
3 years ago
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