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3 years ago

A man pushed on the side ..

Physics

1 answer:

TiliK225 [7]3 years ago

7 0

Answer:

B.will increase the maximum static friction between the box and the floor

Explanation:

Because static friction is the force that keeps an object at rest

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a child stands with each foot on a different scale. The left scale reads 200N and the right scale reads 150N. what is her mass i

vitfil [10]

Answer:

35.7 kg

Explanation:

We are given that

Left scale reads =200N

Right scale reads=150 N

We have to find the mass in kg.

We know that

Weight of child= Sum of two scales=200+150=350 N

Acceleration due to gravity= $9.8 m/s^2$

We know that

Weight= mg

Using the formula

$350=9.8 m$

$m=\frac{350}{9.8}=35.7 kg$

Hence, the mass of child=35.7 kg

4 0

3 years ago

Ask a member of the family to help you.Do the following activities and identify the skill/skills being excited . use a separate

Archy [21]

Answer:

Ok. Thanks.

I'll try it out.

3 0

3 years ago

The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7

poizon [28]

Answer:

$\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=3.32344\times 10^{-7}\ m$

Explanation:

h = Planck's constant = $6.63\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

$W_0$ = Work function = $4.8\times 10^{-19}\ J$

$v_A$ = Velocity of A particle = $7.7\times 10^5\ m/s$

$v_B$ = Velocity of B particle = $5.1\times 10^5\ m/s$

The wavelength is given by

$\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}$

$\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m$

The wavelength $\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m$

The wavelength $\lambda_B=3.32344\times 10^{-7}\ m$

5 0

4 years ago

How do you determine true displacement value of an object that has moved?

WITCHER [35]

Diceplacement is the distance an object has traveled in a certain direction
for example, if you were to walk North for 20m, then east for 40m, the distance you have traveled is 60m however your displacement is the distance between your starting position and your end position;
sqrt(20^2+40^2) = 44.7m
and because displacement is a vector, there needs to be a direction;
sin(theta)=40/44.7
theta=63.4 degrees East of North

therefore the true displacement is 44.7m at 63.4 degrees East of North

3 0

3 years ago

What are Radio/Tv waves?

Lady_Fox [76]

An electromagnetic wave of a frequency between about 104 and 1011 or 1012 Hz, as used for long-distance communication

6 0

3 years ago