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8_murik_8 [283]

3 years ago

6

An atom of the element ____________has an average atomic mass of about 16 amu. A) oxygen B) sulfur C) nitrogen D) no elements ha

ve that mass

1 answer:

DIA [1.3K]3 years ago

3 0

I think its oxygen because It's atomic mass is 15.999.

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an airplane releases a ball as it flies parallel to the ground at a height of 235m. if the ball lands on the ground exactly at 2

Oksanka [162]

<span>When the question says the ball lands a distance of 235 meters from the release point, we can assume this means the horizontal distance is 235 meters. Let's calculate the time for the ball to fall 235 meters to the ground. y = (1/2)gt^2 t^2 = 2y / g t = sqrt{ 2y / g } t = sqrt{ (2) (235 m) / (9.81 m/s^2) } t = 6.9217 s We can use the time t to find the horizontal speed. v = d / t v = 235 m / 6.9217 s v = 33.95 m/s Since the horizontal speed is the speed of the plane, the speed of the plane is 33.95 m/s</span>

7 0

3 years ago

A 1502.7 kg car is traveling at 33.1 m/s when

Bond [772]

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

5 0

3 years ago

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates

34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance $C_{0}$ = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed $3.00 \times 10^{4}$ V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

V = Ed

Now,

Q = CV

or, Q = $C \times Ed$

Therefore, substitute the values into the above formula as follows.

Q = $C \times Ed$

= $8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})$

= $2.55 \times 10^{-10} C$

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is $2.55 \times 10^{-10} C$ .

3 0

3 years ago

Which statement accurately describes the ultraviolet catastrophe

castortr0y [4]

Answer: A hot lightbulb gave off white visible light instead of ultraviolet light.

Explanation:

3 0

3 years ago

A piece of clay sits 0.10 m from the center of a potter’s wheel. If the potter spins the wheel at an angular speed of 15.5 rad/s

finlep [7]

Answer:

$a=24.025\ m/s^2$

Explanation:

Given that

Distance from the center ,r= 0.1 m

The angular speed ,ω = 15.5 rad/s

We know that centripetal acceleration is given as

a=ω² r

a=Acceleration

r=Radius

ω=angular speed

a=ω² r

Now by putting the values in the above equation we get

$a=15.5^2\times 0.1\ m/s^2$

$a=24.025\ m/s^2$

Therefore the acceleration of the clay will be $a=24.025\ m/s^2$ .

4 0

3 years ago