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hodyreva [135]
2 years ago
12

Which describes the electric field at the center of a ring of uniform negative charge?.

Physics
1 answer:
Bingel [31]2 years ago
7 0

Answer:

A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,

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How much heat is required to change 1.0 kg of ice, originally at -20.0 degrees celcius, into steam at 110.0 degrees celcius? Ass
Marizza181 [45]

Answer:

Q = 3087460 J

Explanation:

As we know that first ice will convert into water

then water will heat to 100 degree celcius and then it will converted into vapor and then its temperature is raised to 110 degree C

First we will find the heat to take the ice at 0 degree and then convert it into water

Q_1 = ms_{ice}\Delta T + mL

Q_1 = 1(2100)(0 - (-20)) + 1(335000)

Q_1 = 42000 + 335000 = 377000 J

Now heat required to take it to 100 Degree then convert into vapor and then raise temperature to 110 degree

Q_2 = 1(4186)(100 - 0) + (1)(2250000) + 1(4186)(110 - 100)

Q_2 = 2710460 J

So total heat required is given as

Q = Q_1 + Q_2

Q = 377000 + 2710460

Q = 3087460 J

5 0
2 years ago
A person holding a 15.0 kg containing one 50.0 g bullet is riding on a train that is traveling at 75.0 km/h east. If the man fir
Lana71 [14]

Answer:

The velocity of the gun relative to the ground is 19.66 m/s

Explanation:

Given data,

The mass of the gun, M = 15.0 kg

The mass of the bullet, m = 50 g

The velocity of the train, v = 75 km/h

                                           = 20.83 m/s

The velocity of bullet relative to train, V' = 350 m/s

The velocity of bullet relative to ground, V = 350 + 20

                                                                       = 370 m/s

According to the law of conservation of momentum,

                                Mv' + mV' = 0

                                   v' = -\frac{mV'}{M}

                                   v' = -\frac{0.050\times 350}{15}

                                      = -1.17 m/s

Therefore, the velocity of the gun with,

                                   v₀ = V + v'

                                        = 20.83 - 1.17

                                         = 19.66 m/s

Hence, the velocity of the gun relative to the ground is 19.66 m/s

8 0
3 years ago
What does wave speed have to do with all SONAR AND RADAR technologies?
Elena L [17]

Explanation:

1) Radar uses radio waves, which are a type of electromagnetic energy. Sonar uses the echo principle by sending out sound waves underwater or through the human body to locate objects. Sound waves are a type of acoustic energy. Because of the different type of energy used in radar and sonar, each has its own applications.

2)Radar systems operate using radio waves primarily in air, while sonar systems operate using sound waves primarily in water (Minkoff, 1991). Despite the difference in medium, similarities in the principles of radar and sonar can frequently result in technological convergence.

4 0
2 years ago
Read 2 more answers
PLEASE HELP URGENT!!!!!!!!!!!!!
Nimfa-mama [501]

c i think sorry if wrong

4 0
3 years ago
The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A
love history [14]

Answer:

Part a)

EMF = 14 \times 10^{-3} V

Part b)

EMF = 15.67 \times 10^{-3} V

Explanation:

As we know that magnetic flux through the loop is given as

\phi = B.A

now we have

\phi = B\pi r^2

now rate of change in flux is given as

\frac{d\phi}{dt} = B(2\pi r)\frac{dr}{dt}

now we know that

A = \pi r^2

0.285 = \pi r^2

r = 0.30 m

Now plug in all data

EMF = (0.20)\times 2\pi\times (0.30) \times (0.037)

EMF = 14 \times 10^{-3} V

Part b)

Now the radius of the loop after t = 1 s

r_1 = r_0 + \frac{dr}{dt}

r_1 = 0.30 + 0.037

r_1 = 0.337 m

Now plug in data in above equation

EMF = (0.20)\times 2\pi\times (0.337) \times (0.037)

EMF = 15.67 \times 10^{-3} V

5 0
3 years ago
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