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Yakvenalex [24]
3 years ago
8

Help pls asap!! if you could show me what it should look like that’d be very much appreciated lol

Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

Step-by-step explanation:

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Pythagorean theory m3/9=3
Anna71 [15]

Answer:

Step-by-step explanation:

m3/9=3

We move all terms to the left:

m3/9-(3)=0

We multiply all the terms by the denominator

m3-3*9=0

We add all the numbers together, and all the variables

m^3-27=0

#learnwithbrainly

6 0
2 years ago
A square canvas has an area of 49 square inches. What is the perimeter of the canvas?
a_sh-v [17]

Answer:

Step-by-step explanation:

Area = side*side

side * side = 49

side * side = 7*7

side = 7 inches

Perimeter = 4*side

=4 * 7

= 28 inches

4 0
3 years ago
Read 2 more answers
What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30​
tia_tia [17]

Answer:

16

Step-by-step explanation:

ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30

number of terms =13

median=[(n+1)/2] th term

=[(13+1)/2] th term

=[14/2] th tem

=7th term

=16

7 0
3 years ago
A fraction equal to one for the relationship between these units m/c=1
BigorU [14]

\dfrac{m}{c}=1\ \text{therefore}\ m=c\ and\ m,c\neq0

7 0
3 years ago
Find the volumes of the solids generated by revolving the triangle with vertices (2, 2)​, (2, 6)​, and (5, 6) about ​a) the​ x-a
Vesna [10]
  • About the x-axis (washer method):

\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}

  • About the y-axis (shell method):

\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}

  • About x=7 (shell method):

\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}

  • About y=2 (washer method):

\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}

7 0
3 years ago
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