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kondor19780726 [428]
3 years ago
13

12. An unbalanced 6.0 newton force acts eastward on an object for 3.0 seconds. The impulse

Physics
1 answer:
meriva3 years ago
3 0

Answer:

Impulse=18Ns

Explanation:

Impulse= force*time

Plug in known values...

I=6N*3s

I=18Ns

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SOMEONE HELP  ASAP PLSS
kirill115 [55]

–0.05 m/s

Explanation:

The total momentum of the system player+basketball must be conserved before and after the ball has been thrown.

Before throwing the ball, the total momentum of the system is zero, because can assume both the player and the basketball being at rest:

p_i

The total momentum after the ball has been thrown is instead the sum of the momenta of the the player and of the basketball:

p_f=m_p v_p + m_b v_b

where

m_p = 59 kg is the player's mass

v_p is the player's velocity

m_b=0.51 kg is the ball's mass

v_b=6 m/s is the ball's velocity

For the conservation of momentum, we have

p_i=p_f

0=m_p v_p + m_b v_b

v_p=-\frac{m_b v_b}{m_p}=-\frac{(0.51 kg)(6 m/s)}{59 kg}=-0.05 m/s

And the negative sign means that the player travels in the opposite direction to the ball.

8 0
3 years ago
Read 2 more answers
What will be the effect on the loudness of sound if the amptitude is doubled and halved?
kap26 [50]
<em>remember that
<u>loudness is directly proportional to the square of amplitude...
</u>
so when amplitude is doubled ,,loudness increases four times..
when it is halved ,,,loudness is halved,,,</em>
4 0
3 years ago
Amplitude means that a note has a high pitch.<br><br> true or false
melisa1 [442]
Amplitude does not mean a note has a high pitch
6 0
3 years ago
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Sound will not travel through <br> A. A vacuum<br> B. Solids<br> C. Liquids <br> D. Gases
NARA [144]
Sound will not travel through A vacuum
3 0
3 years ago
Water is pumped from a lake to a storage tank 20 m above at a rate of 95 L/s while consuming 22.3 kW of electric power. Disregar
Luba_88 [7]

Answer:

(a) η = 0.835 = 83.5%

(b) ΔP = 196000 Pa = 196 KPa

Explanation:

(a)

The useful output of the pump-motor system will the power required to pump the water to the storage tank. That power is given as:

P = ρghQ

where,

P = Power to pump = ?

ρ = density of water = 1000 kg/m³

g = 9.8 m/s²

h = height = 20 m

Q = Volume Flow Rate = (95 L/s)(0.001 m³/1 L) = 0.095 m³/s

Therefore,

P = (1000 kg/m³)(9.8 m/s²)(20 m)(0.095 m³/s)

P = 18620 W = 18.62 KW

So, now the efficiency is given as:

η = Desired Output/Required Input

where,

η = overall efficiency = ?

Desired Output = Power to Pump = 18.62 KW

Required Input = Electric Power = 22.3 KW

Therefore,

η = 18.62 KW/22.3 KW

<u>η = 0.835 = 83.5%</u>

(b)The pressure difference between inlet and the outlet is given by the formula:

ΔP = ρgh

where,

ΔP = Pressure Difference = ?

ρ = density of water = 1000 kg/m³

g = 9.8 m/s²

h = height = 20 m

Therefore,

ΔP = (1000 kg/m³)(9.8 m/s²)(20 m)

<u>ΔP = 196000 Pa = 196 KPa</u>

4 0
4 years ago
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