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3 years ago

_____ energy powers the water cycle. Geothermal Solar Latent Electric

2 answers:

6 0

Solar energy is the correct answer. Two of the processes that make up the water cycle need solar energy and these include:

1. Transpiration- as plants absorb water from the soil, the soil, the water moves through the stem to the leaves . Once the water reaches the leaves , some of it evaporates from the leaves, adding to the amount of water vapor in the air. This process of evaporation from the leaves is known as transpiration and requires warmth of the sun (heat energy) to make temperatures jut right for it to take place

2. Evaporation- water that has returned to earth through precipitation and found in rivers, lakes, sea, and ponds when heated by the sun's thermal (solar) heat energy evaporates and as water vapor rises again into the atmosphere.

creativ13 [48]3 years ago

5 0

Answer:

B. Solar energy

Explanation:

Odyssey ware

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In a second order lever system the force ratio is 2.5, the load is at the distance of 0.5m from the fulcrum find distance of eff

Fynjy0 [20]

Answer:

1.25 m

Explanation:

From the question given above, the following data were obtained:

Force ratio = 2.5

Distance of load from the fulcrum = 0.5 m

Distance of effort =.?

The distance of the effort from the fulcrum can be obtained as illustrated below:

Force ratio = Distance of effort / Distance of load

2.5 = Distance of effort / 0.5

Cross multiply

Distance of effort = 2.5 × 0.5

Distance of effort = 1.25 m

Therefore, the distance of the effort from the fulcrum is 1.25 m

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2 years ago

The element chlorine is found in nature as a molecule that can be represented as - A. Cl.

poizon [28]

A
Cl is the chemical symbol for chlorine numbers after it are isotopes

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2 years ago

The engine of a locomotive exerts a constant force of 8.1*10^5 N to accelerate a train to 68 km/h. Determine the time (in min) t

Bumek [7]

Answer:443.1 s

Explanation:

Given

Engine of a locomotive exerts a force of $8.1\times 10^5 N$

Mass of train $=1.9\times 10^7$

Final speed (v) $=68 km/h \approx 18.88 m/s$

F=ma

so $acceleration(a) =\frac{F}{m}=\frac{8.1\times 10^5}{1.9\times 10^7}$

$a=0.042631 m/s^2$

and acceleration is

$a=\frac{v-u}{t}$

$0.042631=\frac{18.88-0}{t}$

$t=443.089 \approx 443.1 s$

8 0

3 years ago

Read 2 more answers

Covalent bonds are formed between BLANK

ololo11 [35]

Covalent bonds are formed through an electrostatic attraction between two oppositely charged ions. Hope this Helps :)

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3 years ago

Read 2 more answers

7. A mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110N @ an angle

jasenka [17]

Weight of the carriage $=(m+M)g =142.1\ N$

Normal force $=Fsin(\theta) + W = 197.1\ N$

Frictional force $=\mu N=27.59\ N$

Acceleration $=4.66\ m\ s^{-2}$

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

So Weight(W) $=(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)$

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with $F_x$ , force of $110\ N$ acting vertically downward.Both are downward and Normal is upward so Normal force $=Summation\ of\ both\ forces$