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Margarita [4]
3 years ago
11

A 10.-newton force is required to hold a stretched spring 0.20 meter from its rest position. What is the potential energy stored

in the
stretched spring?
Physics
1 answer:
tester [92]3 years ago
4 0
Data: 
Ep = ? (Joule)
if: F = k.x → F  = 10 N
x (displacement) = 0.20 m

Formula:
Ep =  \frac{F*x}{2}

Solving:
Ep = \frac{F*x}{2}
Ep =  \frac{10*0.20}{2}
Ep =  \frac{2}{2}
\boxed{\boxed{Ep = 1\:Joule}}\end{array}}\qquad\quad\checkmark


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<u>Answer:</u>

<em><u>The </u></em><em><u>mass </u></em><em><u>of </u></em><em><u>the </u></em><em><u>object </u></em><em><u>is </u></em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Kg.</u></em>

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