<span>Here, g is the acceleration due to gravity at the Earth's surface and is the standard gravity, defined as 9.8m/s....So, the force by that gravity is called g-force.....</span>
Answer:
N= 238 turns
Explanation:
The induced Emf that goes through a solenoid can be calculated using the below formula;
Where ξ=induced Emf
L= self inductance
I= current
ξ= L|dⁱ/dt|
Making L which is the self inductance subject of formula we have
L=ξ/[|dⁱ|*|dt|]
The current here is changing at the rate of
.0260 A/s
L=NΦB/i
N=ξ/Φ|di|*|dt|
Magnitude of the induced Emf given= 12.6mV then if we convert to volt we have 12.6×10⁻³ V
The current I = 1.40A
Magnitude flux through the flux=/0.00285 Wb
Then if we substitute all this Value to equation above we have
N=(12.6×10⁻³ V×1.40A)/(0.00285 Wb×0.0260 A/s)
N=238turn
Therefore, there are 238turns in the solenoid
Answer:
he spring provides the controlling torque. The air friction induces the damping torque, which opposes the movement of the coil. The repulsion type instrument is a non-polarized instrument, i.e., free from the direction of current passes through it. Thus, it is used for both AC and DC
Answer:
θ = 225 rad
Explanation:
given data
angle = 25 rad
to find out
angular velocity after 3t?
solution
let angular acceleration α in t
θ = ω × t + 0.5 × α × t² ........................1
here ω = 0 (initial velocity )
so put this value here
25 = 0 + 0.5 × α × t² ..........................2
α = 25 ÷ (0.5 t²)
α = 50 ÷ t² .........................3
now here we take in 3t
θ = ω × 3t + 0.5 × α × (3t)²
for ω = 0
θ = 0 + 0.5 × α × 9t²
now put value in eq 2
so
θ = (0.5) × (50 ÷ t²) × (3t)²
θ = 25 × 9
θ = 225 rad
