Answer:
Lead metal has a greater magnitude of temperature change.
Explanation:
let the mass of copper and lead be m.
Energy loosed by Copper metal = -Q = -100 J
(Negative sign just indicates that energy is released)
Change in temperature warm of the copper =
Specific heat capacity of copper = c = 0.093 KCal/Kg°C = 389.112 J/kg°C
1 kCal = 4184 Joules
Energy gained by lead metal = Q' = 100 J
Change in temperature lead=
Specific heat capacity of lead = c' = 0.031 KCal/Kg°C = 129.704 J/kg°C
On comparing temperature changes in both metals:
Lead metal has a greater magnitude of temperature change.
Gravitational to Kinetic to Chemical
Explanation:
Power = current × voltage
P = IV
2 W = I (20 V)
I = 0.1 A
Answer:
τ = 132.773 lb/in² = 132.773 psi
Explanation:
b = 12 in
F = 60 lb
D = 3.90 in (outer diameter) ⇒ R = D/2 = 3.90 in/2 = 1.95 in
d = 3.65 in (inner diameter) ⇒ r = d/2 = 3.65 in/2 = 1.825 in
We can see the pic shown in order to understand the question.
Then we get
Mt = b*F*Sin 30°
⇒ Mt = 12 in*60 lb*(0.5) = 360 lb-in
Now we find ωt as follows
ωt = π*(R⁴ - r⁴)/(2R)
⇒ ωt = π*((1.95 in)⁴ - (1.825 in)⁴)/(2*1.95 in)
⇒ ωt = 2.7114 in³
then the principal stresses in the pipe at point A is
τ = Mt/ωt ⇒ τ = (360 lb-in)/(2.7114 in³)
⇒ τ = 132.773 lb/in² = 132.773 psi
Explanation:
Heat = mc(change in temp.)
m=mass , c = specific heat
Rate of flow of heat = heat current = kA/L(T2-T1)
So, mass = density×volume
So, mc(T2-T1)/time =
kA/L(T2-T1)
Substitute the values given as there are a lot of values missing, so the answer can not be obtained.