A buoy, floating in a ripple tank, is at rest when a wave reaches it. The wave has a frequency of 1.25 Hz, and an amplitude of 0
.75 m. What is the magnitude of the buoy’s displacement after 2.20 seconds?
1 answer:
Answer:
y = -6.57 10⁻³ m
Explanation:
The movement of water is an oscillation in the vertical direction that can be approximated as a simple harmonic movement
y = A cos (wt)
where the amplitude is A = 0.75 m and the angular velocity is related to the frequency
w = 2π f
w = 2π 1.25
w = 7.85 rad / s
we substitute
y = 0.75 cos (7.85 t)
we look for the amplitude for a time of t = 2.20 s, remember that the angles are in radians
y = 0.75 cos (7.85 2.20)
y = -0.00657 m
y = -6.57 10⁻³ m
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