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Klio2033 [76]
3 years ago
13

.What is an example of a technology that helps support the idea of continental drift, thus leading to a change in scientific kno

wledge?
Physics
1 answer:
ValentinkaMS [17]3 years ago
8 0
SONAR, satellite radar, GPS, and deep-sea diving vessels all contribute
to accurate MEASUREMENT of the depth and motion of the sea floor, and
of the motion of the continents. 

Once the measurements are known, they can be analyzed to determine
whether OR NOT they support the idea of continental drift, or some other
hypothesis.

Real scientists don't go out looking for evidence to support the ideas
that they want supported.  That kind of approach to research is found
more in the Flat Earth department.
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Just apply Ohm's Law:


I=V/R=12/2.5=4.8A

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An object has a forward force of 100N and a reverse force of 25N. What is the resultant force?
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<u>Given</u><u>:</u>

  • An object has a forward force = 100N

  • An object has a reverse force = 25N

<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>

What is the resultant force?

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During a hurricane in 2008, the Westin Hotel in downtownNew Orleans suffered damage. Suppose a piece of glass dropped near the t
tangare [24]

Answer:

  • <u>77.8 m/s, downward</u>

Explanation:

For uniform acceleration motion, the average speed is equal to half the soum of the initial velocity, Vi, and the final velocity, Vf

  • Average speed = (Vf + Vi)/2

Also, by definition, the average speed is the distance divided by the time:

  • Average speed = distance / time

Then:

  • (Vf + Vi)/2 = 300m/6.62s

Other kinematic equation for uniform acceleration is:

  • Vf = Vi + a×t

Since the window is falling and the air resistance is ignored, a = g (gravitational acceleration ≈ 9.8m/s²)

Replacing the known values we can set a system of two equations:

From (Vf + Vi)/2 = 300m/6.62s

(Vf + Vi) = 2 × 300m/6.62s

  • Vf + Vi = 90.634      equation 1

From Vf = Vi + a×t

Vf - Vi = 9.8 (6.62)

  • Vf - Vi = 64.876     equation 2

Adding the two equations:

  • 2Vf = 155.510

  • Vf = 77.8 m/s downward (velocities must be reported with their directions)
8 0
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