Answer:
w2=5.1736x10^-6m
Explanation:
The relation between the wavelength and width is:
sin(Ф)=m*λ/w
Since the mass and the angle is the same in both cases so:
sin(Ф)=m*λ1/w1
sin(Ф)=m*λ2/w2
The mass and the sinФ are factor in both elements so:
λ2/w2=λ1/w1
w2=w1*λ2/λ1
w2=4.1x10^-6m*665x10^-9m/527x10^-9m
w2=5.1736x10^-6m
Answer:
854.39 N
Explanation:
The formula for the fundamental frequency of a stretched string is given as,
f = 1/2L√(T/m)..................... Equation 1
Where f = fundamental frequency, L = Length of the wire, T = Tension, m = mass per unit length.
Given: f = 261.6 Hz, L = 0.6 m, m = (5.2×10⁻³/0.6) = 8.67×10⁻³ kg/m.
Substitute into equation 1
261.6 = 1/0.6√(T/8.67×10⁻³)
Making T the subject of the equation,
T = (261.6×0.6×2)²(8.67×10⁻³)
T =854.39 N
Hence the tension of the wire is 854.39 N.
B is the answer because of its throwing the other 2 have potential energy
Answer:
The correct solution will be "271.95 N".
Explanation:
The given values are:
velocity
v = 3.5 m/s
mass
m = 9.0 kg
r = 0.6 m
According to the question:
⇒
⇒
On substituting the values, we get
⇒
⇒
⇒
Answer:
Consider frames X and Y:
If X sees Y moving to his right then Y must see X moving to his right.
If this is not true then one can choose one frame over the other ( a favored frame and this is not allowed)